Calculating Orbital Speed of a Satellite Orbiting Jupiter | Step-by-Step Guide"

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SUMMARY

The discussion focuses on calculating the orbital speed of a satellite orbiting Jupiter at a height of 5.19 x 105 m above its surface. The mass of Jupiter is given as 1.90 x 1027 kg, and its radius is 7.14 x 107 m. The correct formula for orbital speed is v = sqrt[GM/r], where G is the universal gravitational constant (6.67 x 10-11 m3kg-1s-2). Participants emphasize the importance of using the correct values for G and the total radius (r) in calculations to achieve accurate results.

PREREQUISITES
  • Understanding of gravitational physics, specifically Newton's law of universal gravitation.
  • Familiarity with the formula for orbital speed: v = sqrt[GM/r].
  • Knowledge of the universal gravitational constant (G = 6.67 x 10-11 m3kg-1s-2).
  • Basic arithmetic skills for performing calculations involving scientific notation.
NEXT STEPS
  • Review the derivation of the orbital speed formula v = sqrt[GM/r].
  • Practice calculating orbital speeds for different celestial bodies using their respective masses and radii.
  • Explore the concept of gravitational potential energy and its relation to orbital mechanics.
  • Learn about the effects of altitude on orbital speed and satellite stability.
USEFUL FOR

Students studying physics, particularly those focused on celestial mechanics, as well as educators and anyone interested in understanding satellite dynamics around massive bodies like Jupiter.

agadag
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Please help asap! Orbital speed

Homework Statement




A satellite is placed in orbit 5.19x105m above the surface of Jupiter. Jupiter has a mass of 1.90x1027kg and a radius of 7.14x107m. Find the orbital speed of the satellite.
Answer = m/s


Homework Equations



v = sqrt [GM/r]
= (5.19 * 10^5)(1.90*10^27)/ (7.14*10^7+5.19*10^5) = 3.703 *10^12 is wrong!
 
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Use G = 6.67 x 10^-11.
 


ahhh i still didn't get the right answer..? maybe I am just doing my arithmatic wrong. but why would gravity = 6.67?
 


G in the equation is the universal gravitational constant which has the value given by Delphi.For some reason you seem to have used the height of the orbit instead of G.
 


well i assumed since we don't know the gravity of that planet the length of the orbit would be equal to the G. However, I am still not able to get the right answer using either method...
 


I should say the length of the distance from the satellite to the planet... not the length of orbit...
 


G is the universal gravitational constant,it applies to all planets,all masses,everything,it is completely different to distance.My best advice is to look at the theory behind this otherwise you are just fiddling around. To get the right answer you just need to plug the right numbers in your calculator.In your original attempt you had the wrong value for G so try again.
 


yea i tried it again. still no success. I think i give up now.
 


agadag said:
yea i tried it again. still no success. I think i give up now.

Did you calculate the right value for r?
7.14*10^7+5.19*10^5=7.19*10^7(approximately)
Did you take the square root at the end?
 

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