Finding the radius of the satellite's circular orbit

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Specter
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Homework Statement



My title was supposed to say "Finding the radius of the satellites circular orbit" but I can't seem to edit it.
<< Mentor Note -- Title fixed for you >>

A 500 kg satellite experiences a gravitational force of 3000 N, while moving in a circular orbit around the earth.

a) Find the radius of the circular orbit.
b)Find the speed of the satellite.
c)Find the period of the orbit.

Homework Equations


r=√Gm1m2/g

The Attempt at a Solution


I think I have the question set up properly but I can't figure out how to solve it on paper because my calculator won't do it. I keep getting a different answer than what the correct one is.

Part a)

r=√Gm1m2/g
r=√(6.67 x 10-11)(5.98 x 1024)(500)/3000

So the correct answer (at least what others are getting) is 8.15 x 106 but I am getting 148859.74. I've tried putting it into my calculator a few different ways but I can't get the right answer. Do I have to do this on paper? If so, how?

b) I need to find the answer from part a to solve part b, but I know how to set up the question.

v2=Gme/r
v=√Gme/r

c) I am not sure how to do part c, but I think I need to solve part b before I can do this.
 
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At a guess, you are not using parentheses correctly in typing into the calculator. You certainly have not used them correctly in your post.
Please repost your equations with the right usage.
 
haruspex said:
At a guess, you are not using parentheses correctly in typing into the calculator. You certainly have not used them correctly in your post.
Please repost your equations with the right usage.

r=√Gm1m2/g
r=√[(6.67 x 10-11)(5.98 x 1024)(500)]/3000

Is this better?
 
Specter said:
r=√Gm1m2/g
Taken literally, that means r=(√G)1m2/g. I don't think that is what you mean.
Also, your g appears to stand for a force.
Specter said:
r=√[(6.67 x 10-11)(5.98 x 1024)(500)]/3000
and that is wrong.
Go back to the basic gravitational equation, F= etc., and start again.