Calculating Original Speed from Time and Velocity Changes on a Freeway

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Homework Help Overview

The problem involves determining the original speed of a vehicle on a freeway based on changes in speed and time taken to travel a mile. The context includes the relationship between speed, distance, and time, specifically focusing on how an increase in speed affects travel time.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss setting up equations based on the relationships between speed, distance, and time. There are attempts to manipulate these equations to express one variable in terms of another, along with questions about the correct integration of variables.

Discussion Status

The discussion is active, with participants providing guidance on how to approach the problem. There are indications of progress as participants refine their equations and check for consistency in units. However, there is no explicit consensus on a final solution.

Contextual Notes

Participants are working under the constraints of the problem statement, which involves specific changes in speed and time. There are also indications of potential errors in calculations that are being addressed throughout the discussion.

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Homework Statement


Driving along a crowded freeway, you notice that it takes a time t to go from one mile marker to the next. When you increase your speed by 4.5 mi/h, the time to go one mile decreases by 10 s. What was your original speed?


Homework Equations



V=D/T

The Attempt at a Solution



V1T1 = 1 mi
v2t2= i mile
v2= v1 + change of V
t2= t1 - change of t
I then used equations 3 and 4 to eliminate v2 and t2 in equation 2.
(v1 + change of V)(t1 - change of t) = 1 mi

I know that i need to get rid of t1 now, and i should probably use the first equation (v1t1 = 1 mi) to do it. I just don't know how to integrate the two of them.
Thank you in advance
 
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You have two equations and two unknowns: v_1 and t_1. Solve them in the usual way: solve one for one of the unknowns and substitute the result in the other equation.
 
That's what i thought i was doing. by putting in v1t1=1mile into (v1 + change in v)(t1-change in t). but would that be (v1 + change in v)(v1 - change in t)? or (v1 + change in v)((1/v1) - change in t)?
 
The second one (if you add units), as V1T1=1mile is equivalent to T1=1mile/V1.
 
Ah ok. so then i just simplify that equation to find v1.
which would be.. (v12)(Δt) + (ΔvΔt) - (Δv)(1 mi) = 0

so then i do quadratic?
 
That is a good idea, indeed. But the units of the last equation are wrong, there is some error in the calculation.
 
(Δt)v12 + (Δv)(Δt)v1 - (Δv)(1mi) = 0

fixed?
 
Now the units match. I didn't check the equations, but you can check the result yourself afterwards with known v1 and t1.
 
i got the right answer.
thank you
 

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