Calculating Percent Yield for a Chemical Reaction

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SUMMARY

The discussion focuses on calculating the percent yield of sodium chloride (NaCl) from a reaction involving sodium bromide (NaBr) and potassium chloride (KCl). The theoretical yield of NaCl is calculated to be 14.201 grams based on the stoichiometry of the reaction. Given an actual yield of 18 grams, the percent yield is determined to be 78.9%. The calculation method is confirmed to be correct, with a note on the importance of significant figures in reporting results.

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  • Understanding of stoichiometry in chemical reactions
  • Knowledge of molar mass calculations
  • Familiarity with the concept of theoretical vs. actual yield
  • Ability to perform percentage calculations
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  • Learn about significant figures and their importance in chemical calculations
  • Explore advanced stoichiometric calculations involving multiple reactants
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Homework Statement



1. If we mix 25 grams of sodium bromide with a large amount of potassium chloride, what will our theoretical yield of sodium chloride be?

2. If our actual yield from this reaction was 18 grams of sodium chloride, what would our percent yield for this reaction be?


The Attempt at a Solution



1. NaBr + KCl ------> NaCl + KBr

MNaBr = 25gNaBr ÷ 102.9gNaBr = 0.243molNaBr
0.243molNaBr x 1molNaCl/1molNaBr = 0.243molNaCl
0.243molNaCl x 58.44gNaCl/1molNaCl
= 14.201g NaCl

2. 14.201/18 x 100 = 78.9%


Is this correct? Thank you!
 
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In general too many significant figures, but other than that NaCl mass is OK.

What is definition of the percent yield?

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