Theoretical Yield of CaCO3: Calculate & Round

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Discussion Overview

The discussion revolves around calculating the theoretical yield of calcium carbonate (CaCO3) from a reaction involving calcium chloride dihydrate (CaCl2•2H2O) and sodium carbonate (Na2CO3). Participants are attempting to clarify the steps involved in the calculation, including the correct use of molar masses and the implications of the dihydrate form of calcium chloride.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant presents a calculation involving the molar mass of calcium chloride but seems confused about the dihydrate aspect and its impact on the calculation.
  • Another participant points out that the initial calculation neglected the water content in the dihydrate and suggests that the question is about calcium carbonate, indicating a possible typo.
  • Several participants express confusion about the term "dihydrate" and its meaning, with varying degrees of understanding about how it relates to the calculation.
  • One participant attempts to clarify the concept of a hydrate and its stoichiometric implications in the context of the problem.
  • Another participant provides a calculation but is met with a correction regarding the misunderstanding of the hydrate's role in determining molar mass.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct approach to the calculation, and there is ongoing confusion regarding the concept of hydrates and their implications for the molar mass. Multiple competing views and interpretations of the problem remain evident throughout the discussion.

Contextual Notes

There are limitations in the understanding of the term "dihydrate" and its relevance to the calculation of molar mass, as well as unresolved steps in the calculation process. The discussion reflects varying levels of familiarity with the concepts involved.

aquablue8
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Homework Statement



What is the theoretical yield of calcium carbonate if 2.07 grams of calcium chloride dihydrate reacts with excess sodium carbonate according to the balanced chemical reaction shown below?

Homework Equations



Please use molar mass values calculated and rounded to the hundreths place, and round your answer to the hundredths place.

CaCl2•2H2O(aq)+Na2CO3(aq)→CaCO3(aq)+2NaCl(aq)+2H2O(l)

The Attempt at a Solution



I got the molar mass of CaCl2, which is 110.98, then I divided it by 2.07 g of CaCl2 which is the actual?? Am I way off track? That got me 229.73g CaCl2?
 
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aquablue8 said:
I got the molar mass of CaCl2, which is 110.98, then I divided it by 2.07 g of CaCl2 which is the actual?? Am I way off track? That got me 229.73g CaCl2?

While calculating molar mass you ignored fact that you deal with dihydrate, and your answer refers to calcium chloride, while question asks about carbonate. I guess the latter is just a typo.
 
I do not understand what you mean. Where did I go wrong in lay-woman's terms? lol!
 
On the second read I see you confused much more than I saw earlier.

Let's start from the very beginning. What does it mean "dihydrate"?
 
Two hydrations?
 
Oops. What is hydrate?
 
To add 2 hydrogen bonds by dehydration synthesis?
 
Umm, I am really lost now!
 
  • #10
Okay, so two hydrogen bonds hydrated the solution??
 
  • #11
Here is what I have attempted: 2.07gCaCl2 x 1 mol Ca/40.08g Ca x 2 mol Cl/2 mol Ca x 70.9g Cl2/ 1 mol Cl2 = 3.62 g CaCl2
 
  • #12
No.

Hydrate means when substance crystallizes it crystallizes with water, and there is a stoichiometric ratio of water to the substance. In this particular case you are told it is dihydrate, which means its formula is CaCl2.2H2O - you have even written it this way (correctly) in your first post. That means you need to accommodate for the water presence when calculating molar mass of the substance.

aquablue8 said:
Here is what I have attempted: 2.07gCaCl2 x 1 mol Ca/40.08g Ca x 2 mol Cl/2 mol Ca x 70.9g Cl2/ 1 mol Cl2 = 3.62 g CaCl2

As explained at CF - 2 does not equal 3.
 
  • #13
Thank you for your help!
 

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