Calculating Period of Mars Using Kepler's Law: Appendix C

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SUMMARY

The discussion focuses on calculating the orbital period of Mars using Kepler's Law of periods, specifically the formula T^2 = [4 x (pi)^2 x r^3]/[GM]. The mean distance of Mars from the Sun is 1.52 times that of Earth, leading to a calculated period of 1.88 years, which matches the value stated in Appendix C. Participants emphasize the simplification of the equation to T^2 = a^3 for easier calculations, where 'a' represents the semi-major axis in astronomical units.

PREREQUISITES
  • Understanding of Kepler's Laws of planetary motion
  • Familiarity with the formula T^2 = [4 x (pi)^2 x r^3]/[GM]
  • Basic knowledge of astronomical units (AU)
  • Ability to perform algebraic manipulations
NEXT STEPS
  • Study the derivation of Kepler's Laws of planetary motion
  • Learn how to apply the simplified equation T^2 = a^3 for different planets
  • Explore the concept of astronomical units and their significance in celestial mechanics
  • Investigate the gravitational constant (G) and its role in orbital calculations
USEFUL FOR

Astronomy students, educators, and anyone interested in celestial mechanics and the calculations of planetary orbits.

Collegestudent5
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The mean distance of Mars from the Sun is 1.52 time that of Earth from the Sun. From Kepler's law of periods, calculate the number of years required for Mars to make one revolution around the Sun; compare your answer with the value given in Appendix C.


Kepler's Law of periods is: T^2=[4 x (pi)^2 x r^3]/[GM]

Appendix C says the Period=1.88 y

I have no idea how to begin this problem. Please help set me in the right direction.
 
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