Kepler's Law to Determine Period of Asteroid

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SUMMARY

The discussion centers on applying Kepler's Third Law to determine the orbital period of an asteroid that orbits at twice the Earth-Sun distance (2 AU). Using the formula T² = Kr³, where K is defined as 4π²/GM, the participants conclude that if K is set to 1, then R³ equals 8, leading to a period T of approximately 2.83 years. This calculation aligns with the established understanding of celestial mechanics as described by Kepler's laws.

PREREQUISITES
  • Understanding of Kepler's Third Law of planetary motion
  • Familiarity with the gravitational constant (G) and mass of the Sun (M)
  • Basic knowledge of astronomical units (AU)
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the derivation of Kepler's Third Law in detail
  • Explore the implications of gravitational constants in celestial mechanics
  • Learn about the calculation of orbital periods for various celestial bodies
  • Investigate the relationship between distance and period in multi-body systems
USEFUL FOR

Astronomy students, educators in physics, and anyone interested in celestial mechanics and the calculations of orbital dynamics.

scrambledeggs
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Homework Statement



A newly discovered asteroid orbits at twice the Earth-Sun distance. Find its period of orbit (in years).

Homework Equations



I know that I'm supposed to use Kepler's third law to determine this.
T2 = Kr3
K = 4∏2/GM

and the Earth-Sun distance is of course 1 Au

The Attempt at a Solution



I know that the answer should be √8 or about 2.83 years I just don't know how to get there. So frustrating because I know that this is a simple question.

Could it be that K = 1, and R=2 therefore R3 = 8?
 
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scrambledeggs said:

Homework Statement



A newly discovered asteroid orbits at twice the Earth-Sun distance. Find its period of orbit (in years).

Homework Equations



I know that I'm supposed to use Kepler's third law to determine this.
T2 = Kr3
K = 4∏2/GM

and the Earth-Sun distance is of course 1 Au

The Attempt at a Solution



I know that the answer should be √8 or about 2.83 years I just don't know how to get there. So frustrating because I know that this is a simple question.

Could it be that K = 1, and R=2 therefore R3 = 8?

Think about the relationship between this asteroid's orbit and the Earth's orbit.
 

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