To calculate the change in pH after adding 10.0 mL of 1.0M HClO4 to 990.0 mL of water, start by using the pH formula, pH = -log[H+]. Assuming HClO4 is nearly 100% dissociated, determine the initial concentration of H+ ions from the original solution. Next, calculate the new diluted concentration of HClO4 after mixing, and then find the new pH using this concentration. Finally, subtract the original pH from the new pH to determine the change, which is noted to be 2.
#1
answerseeker
27
0
when you add 10.0 mL of 1.0M HClO4 into 990.0mL water, the pH changes by 2.
how would you find the change in pH?
1. Write out the expression that defines pH
2. Assume HClO4 is close to 100% dissociated in solution
3. From the original concentration of HClO4, find [H+] and calculate the original pH from this
4. Calculate the new (diluted) concentration of HClO4 (molarity = number of moles/volume of solution)
5. Using the new value of [H+], calculate pH again.
6. Subtract from the original number to find the difference.
I came.across a headline and read some of the article, so I was curious.
Scientists discover that gold is a 'reactive metal' by accidentally creating a new material in the lab
https://www.earth.com/news/discovery-that-gold-is-reactive-metal-by-creating-gold-hydride-in-lab-experiment/
From SLAC - A SLAC team unexpectedly formed gold hydride in an experiment that could pave the way for studying materials under extreme conditions like those found inside certain planets and stars undergoing...