Calculating pH of Na3PO4 and NaH2PO4 Solution with Ka Values for H2CO3

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SUMMARY

The discussion focuses on calculating the pH of a solution containing 50ml of 0.10M Na3PO4 and 50ml of 0.10M NaH2PO4, utilizing the dissociation constants (Ka) for H2CO3: Ka1 = 7.5 * 10^{-3}, Ka2 = 6.2 * 10^{-8}, and Ka3 = 1.0 * 10^{-12}. The participant initially considered only the hydrolysis of Na3PO4 due to its high K_h compared to Ka2, but recognized that this approach was incorrect. The mixture represents a buffer system with equimolar amounts of a weak acid and its conjugate base, suggesting that the pH can be determined using the Henderson-Hasselbalch equation.

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Homework Statement



50ml of 0.10M Na_3PO_4 + 50ml of 0.10M NaH_2PO_4

For H_2CO_3:
Ka_1 = 7.5 * 10^{ - 3}
Ka_2 = 6.2 * 10^{ - 8}
Ka_3 = 1.0 * 10^{ - 12}


Homework Equations





The Attempt at a Solution



Since K_h of Na_3PO_4 > > Ka_2 , I considered only hydrolysis of Na_3PO_4 but it gives wrong answer.
 
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You have a mixture of a weak acid and its conjugate base - does it ring a bell?
 
Actually, there are so many equilibria in this solution I can't figure out what will contribute and the assumption I made(given above) seems to give a wrong answer.
 
Actually my previous comment was not too good :frown:

Think this way: you have mixed equimolar amounts of Na3PO4 and NaH2PO4. Does it differ from just dissolving Na2HPO4?
 

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