Calculating Potential Difference Between Points A and B

  • Thread starter Thread starter mujadeo
  • Start date Start date
  • Tags Tags
    Pd Points
Click For Summary
SUMMARY

The discussion focuses on calculating the potential difference between points A and B in a circuit with a current of 2A. The circuit includes a 3-ohm resistor and a 1-ohm resistor, with a -20V battery and a +6V battery. The potential difference is derived using Ohm's Law (V = IR) and Kirchhoff's loop rule to analyze the voltage contributions from the components. The correct approach involves summing the voltages around the loop to determine the net potential difference.

PREREQUISITES
  • Understanding of Ohm's Law (V = IR)
  • Familiarity with Kirchhoff's Voltage Law
  • Basic circuit analysis skills
  • Knowledge of series and parallel resistor configurations
NEXT STEPS
  • Study Kirchhoff's Voltage Law in detail
  • Practice circuit analysis with various resistor configurations
  • Learn about the effects of EMF in circuits
  • Explore advanced topics in electrical engineering, such as Thevenin's and Norton's theorems
USEFUL FOR

Students studying electrical engineering, physics enthusiasts, and anyone seeking to improve their circuit analysis skills.

mujadeo
Messages
103
Reaction score
0

Homework Statement


a current of 2A is flowing from a to b.
what is the potential difference between the points?

______a______3ohm_____-20V+_____1ohm_______+6V-________b_____


hopefully my diagram makes sense.


Homework Equations


this is a really simple question and i can't answer it because I am not understanding the whole concept.
Does current (or anything) stay constant in a cicuit??
do i follow the current round/thru circuit and do calcs along the way?
so voltage after 3ohm-R = IR = 6V
so 6V into 20V battery. now I am stuck. it goes into neg term first so is that -20V?? please help somene! thanks


The Attempt at a Solution

 
Physics news on Phys.org
If you assume a battery of EMF E volt is connected across the a and b such that a end is +ve and b end is -ve. Apply loop law, and find E. If you get E +ve, signs of a and b correct. If you get E -ve, reverse the signs of a and b.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K