Calculating Potential Energy of Three Point Charges

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SUMMARY

The discussion focuses on calculating the potential energy (PE) of three point charges: Q1 = 2.9 μC, Q2 = 4.9 μC, and Q3 = 3.9 μC, using the formula PE = k(q1q2/r + q1q3/r + q2q3/r), where k = 8.99 x 10^9 N m²/C². Participants emphasize the importance of using the correct charge values in scientific notation, specifically converting microcoulombs to coulombs (e.g., 2.9 μC to 2.9e-6 C). The discussion also highlights the necessity of recognizing that the distance "r" varies for each pair of charges.

PREREQUISITES
  • Understanding of electrostatics and Coulomb's law
  • Familiarity with potential energy calculations in physics
  • Knowledge of scientific notation and unit conversions
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation of the potential energy formula for multiple point charges
  • Learn about the significance of the Coulomb constant (k) in electrostatics
  • Explore the concept of electric field and its relation to potential energy
  • Practice problems involving multiple point charges and varying distances
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Students studying physics, particularly those focusing on electrostatics, as well as educators and tutors looking to enhance their understanding of potential energy calculations involving point charges.

disque
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Homework Statement



Three point charges Q1 = 2.9 mu or micro C, Q2 = 4.9 mu or micro C and Q3 = 3.9 mu or micro C, are arranged as shown.

Homework Equations



PE=k(q1q2/r+q1q3/r+q2q3/r)
k=8.99e9

The Attempt at a Solution



By using that equation I plugged in the lengths and changed the 2.9 to micro coulombs.
 

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disque said:

Homework Equations



PE=k(q1q2/r+q1q3/r+q2q3/r)
k=8.99e9

The Attempt at a Solution



By using that equation I plugged in the lengths...
Sounds like you have the right idea. You realize that "r" is different for each pair of charges, right?

... and changed the 2.9 to micro coulombs.
I'm not sure what that means. Just use 2.9e-6 C, etc., for the charge values.
 
yea i got it, i had a negative sign and it was positive. not really sure why but thanks for your help
 

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