Calculating Power & Torque for Flywheel Drives

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Discussion Overview

The discussion revolves around calculating the appropriate motor power and torque required to drive a flywheel at a maximum speed of 2000 rpm, as well as the resulting power at a 750 rpm pulley. Participants explore the implications of friction and losses in real systems versus ideal conditions.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant seeks to determine the motor power and torque needed for a flywheel system, referencing two figures for context.
  • Another participant states that in an ideal lossless system, power out at 750 rpm equals power in at 3000 rpm, but real systems must account for losses due to friction and other factors.
  • Several participants emphasize that the calculations depend on friction, noting that without friction, maintaining constant speed requires no power.
  • There is a reiteration that real flywheels experience friction and power loss, which complicates the calculations.
  • One participant expresses a need to calculate values under the assumption of no friction and constant speed.
  • Another participant warns against the misconception that a flywheel can output more power than is input, citing the laws of physics.

Areas of Agreement / Disagreement

Participants generally agree that friction plays a critical role in determining power requirements, but there is no consensus on the specific calculations or assumptions to be used, particularly regarding the presence or absence of friction.

Contextual Notes

Participants have not provided specific values for friction or other losses, leaving the calculations dependent on these unspecified factors. The discussion also reflects a mix of idealized scenarios and practical considerations.

Bassam Salman
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Hi
I have a personal project, In link bellow in figure A I need to calculate appropriate power motor (HP) and torque (N.M) to drive flywheel at maximum speed 2000 rpm and what is value of resulting power on 750 rpm pulley.
In figure B if we use two flywheel the weight for each half weight of flywheel in figure A do motor power and resulting power equal to figure A

http://img3.file-upload.com/i/00209/utjydznopqfe.png
 
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At steady state, in an ideal (lossless) system, the power out at 750 rpm will be equal to the power in at 3000 rpm.

Since no real system can be built without losses, you will need to account for the losses in the system to see how much power can be drawn out. Much depends on the quality of your bearings, the alignment of shafting, and the windage of the several elements.
 
:welcome:

Your answer depends on friction. The information you provided says nothing about friction.

With zero friction it takes zero power to maintain a rotation at constant speed.

Are you sure that the question is related to constant speed rather than acceleration?
 
Real life flywheels have friction and thus power loss.
 
Dr.D said:
At steady state, in an ideal (lossless) system, the power out at 750 rpm will be equal to the power in at 3000 rpm.

Since no real system can be built without losses, you will need to account for the losses in the system to see how much power can be drawn out. Much depends on the quality of your bearings, the alignment of shafting, and the windage of the several elements.
Is that mean no power loss on flywheel
 
anorlunda said:
:welcome:

Your answer depends on friction. The information you provided says nothing about friction.

With zero friction it takes zero power to maintain a rotation at constant speed.

Are you sure that the question is related to constant speed rather than acceleration?

Now I need calculate without friction and at constant speed
 
An ideal flywheel requires no power to run at constant rotational speed. Real flywheels (and every other machine part as well) always involve friction at bearings and windage. How much these friction losses are depends upon the shapes, the speeds involved, and the surrounding fluid medium.
 
Bassam Salman said:
Now I need calculate without friction and at constant speed

You are not understanding because I already gave you the answer.

anorlunda said:
With zero friction it takes zero power to maintain a rotation at constant speed.

@Dr.D is telling you the same thing I am.

Edit: rearranged the above.
 
Ok thank you Dr. D and anorlunda
I need value of motor size (calculation) and also calculate out power
 
  • #10
Bassam Salman said:
I need value of motor size (calculation) and also calculate out power
If there is no friction, the output power is equal to the input power; the flywheel doesn't change that.

You aren't thinking that the flywheel let's you get more power out than you put in, are you? That would violate the laws of physics and therefore the rules of this forum...
 

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