Calculating power without distance?

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Homework Help Overview

The discussion revolves around calculating the average power developed by a vehicle that accelerates to a certain speed over a specified time without a given distance. The problem involves concepts from kinetic energy and power in the context of physics.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants explore the relationship between kinetic energy and power, questioning the necessity of distance in power calculations. Some suggest that average power can be inferred from energy changes over time, while others express confusion about the role of distance in the formulas.

Discussion Status

The discussion is active, with participants sharing different perspectives on the formulas for power and work. Some guidance is offered regarding the calculation of average velocity and its implications for determining distance, but no consensus has been reached on the best approach to the problem.

Contextual Notes

Participants note the absence of distance in the problem setup, which is leading to uncertainty about how to proceed with the calculations. There is also mention of the constraints imposed by homework rules regarding the use of formulas.

fattydq
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So here's my homework problem:

Calculate KE of a 1500 kg vehicle moving at 30 m/2. Which I did, and got 675000 joules, using the standard KE formula.

But then it asks, if the vehicle accelerated to this speed in 20 seconds, what average power was developed?

Any formula for power involves a distance, which is not given here at all. Can someone help me out? Is it a trick question?
 
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fattydq said:
So here's my homework problem:

Calculate KE of a 1500 kg vehicle moving at 30 m/2. Which I did, and got 675000 joules, using the standard KE formula.

But then it asks, if the vehicle accelerated to this speed in 20 seconds, what average power was developed?

Any formula for power involves a distance, which is not given here at all. Can someone help me out? Is it a trick question?

If it acquires its energy in some amount of time, that implies an average power level input during that time interval...
 
As long as the acceleration is constant, the average velocity is the average of the starting and ending velocities. You can use that to find the average kinetic energy.

And I am surprised to hear that "Any formula for power involves a distance". I was under the impression that "power" was "rate of change of energy over time".

(You could, of course, calculate the distance moved at a constant acceleration in a given time. For constant acceleration, a, and time, t, the velocity is at. You can use that to find a from the information given. The distance moved is [itex](1/2)at^2[/itex].)
 
Well the reason I thought I needed a distance was because the formula for power is the change in work over the change in time. SOOOO the formula for work is force times DISTANCE. So I don't understand how can I calculate power if I can't find work.
 
fattydq said:
Well the reason I thought I needed a distance was because the formula for power is the change in work over the change in time. SOOOO the formula for work is force times DISTANCE. So I don't understand how can I calculate power if I can't find work.

It's not change in work, it's amount of work (or energy) in some amount of time.
 
berkeman said:
It's not change in work, it's amount of work (or energy) in some amount of time.

So I just divide the numerical answer for kinetic energy by 20?
 
fattydq said:
So I just divide the numerical answer for kinetic energy by 20?

I believe that is correct.
 

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