Calculating Pressure Difference in a Vertical Water Pipe

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SUMMARY

The discussion focuses on calculating the pressure difference in a vertical water pipe extending 420 meters, specifically from the bottom to the top of the World Trade Center in New York City. The correct formula used is p(y) = p - ρgy, where ρ is the density of water, which is 1000 kg/m³, not 1 kg/m³ as initially stated. The accurate calculation yields a pressure difference of approximately 0.0407 atm, derived from the equation ρgy = (1000 kg/m³)(9.81 m/s²)(420 m) resulting in 4120.2 Pa, which converts to atm using the conversion factor of 1 atm = 101300 Pa.

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Homework Statement



A vertical water pipe extends from the bottom to the top of the World Trade Center in the Big Apple (New York City), a distance of about 420 m. Calculate the difference in pressure in atm between the bottom and the top of the water pipe.

Homework Equations



p(y) = p - [tex]\rho[/tex]gy

The Attempt at a Solution



[tex]\rho[/tex]gy = (1 kg/[tex]m^{3}[/tex]) (9.81m/[tex]s^{2}[/tex]) (420m)
[tex]\rho[/tex]gy = 4120.2 Pa
4120.2 Pa (1 atm / 101300 Pa) = .0407 atm

The answer above was wrong. Thanks for the help!
 
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The density of water isn't 1kg/m^3. It's 1000kg/m^3!
 
ohhh, that's what was wrong. thanks a lot! :smile:
 

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