Pressure at the bottom of a glass pipe?

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Homework Help Overview

The problem involves calculating the pressure at the bottom of a glass pipe containing three different liquids: water, olive oil, and mercury. The context includes specific densities and a cross-sectional area for the pipe.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the setup of a free body diagram and the forces acting on the system. There is a question about how to proceed after establishing the equilibrium condition. Some participants suggest that calculating the heights or incremental pressures of the individual liquids may not be necessary, while others inquire about the total weight of the liquid.

Discussion Status

The discussion is ongoing, with various approaches being considered. Some participants are exploring the implications of the total mass and gravitational force on the pressure calculation, while others are questioning the need for detailed height calculations.

Contextual Notes

Participants are working within the constraints of a homework problem, which may limit the information available or the methods they can use to arrive at a solution.

KoontzyN
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Homework Statement


Given a cross sectional area of A=10cm^2
1kg each of water ( ρ = 1000 kg/m^3 ), olive oil (
ρ = 800 kg/m^3 ), and mercury ( ρ = 13600 kg/m^3 ) are poured, and allowed to settle. What is the
pressure at the bottom of the pipe?

Homework Equations


F=PA
P=Po+ρgd

The Attempt at a Solution


I have set up a free body diagram of the system with ∑Fy= PA-mg-PoA= o, but I'm not sure what to do at this point.
 
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Solve for the pressure at the bottom?
 
You know how much total mass is supported by the bottom surface. You know the acceleration of gravity. You know the area of the bottom surface. Calculating the heights or incremental pressures from the individual sections is not necessary.
 
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What is the total weight of liquid?
 

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