The discussion centers on calculating the pressure required for a hydraulic lift with an 8-inch diameter cylinder to lift 6000 lbs. The correct formula used is f = pa, where 'f' is the force in pounds and 'a' is the area in square inches. The area is calculated as A = π(r^2), resulting in an area of approximately 50.265 in². The final pressure calculation should yield 119 psi, emphasizing the importance of using consistent units without converting pounds to Newtons.
PREREQUISITESEngineering students, automotive technicians, and professionals working with hydraulic systems who need to understand pressure calculations for lifting mechanisms.
do not convert...leave in pounds of forcetogo said:Homework Statement
the hydraulic lift for an automobile service garage has a cylinder with a diameter of 8 inches. What pressure must the oil have to be able to lift 6000 lbs?
Homework Equations
f=pa
area = pi(r^2)
The Attempt at a Solution
6000 lbs = 26 688 Newtons
units...A = 50.265 in^28 inches = 3.14 x 16 = 50.265
If the problem is given in units of inches and pounds, do not convert pounds to Newtons.26 688/50.265 = 530.9 psi (should be 119 psi)