Calculating Probability for a Discrete Random Variable

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Homework Help Overview

The discussion revolves around calculating the probability for a discrete random variable defined by a probability density function (p.d.f.) with specific values and a constant. The original poster seeks assistance in determining the probability P(1 < X ≤ 3.5) based on the given p.d.f.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to find the constant c and calculate the probability using the p.d.f. Some participants question the validity of the approach, particularly regarding the use of a continuous range for a discrete variable.

Discussion Status

Participants are exploring different interpretations of the problem, with some expressing confusion about the application of the p.d.f. and the constraints of the discrete random variable. There is no explicit consensus, but guidance has been offered regarding the nature of the variable.

Contextual Notes

Some participants note constraints related to the course requirements, such as the prohibition of calculus methods, which may affect the approaches discussed. Additionally, there is mention of a lack of examples provided in class, contributing to the confusion.

bethanyd
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Homework Statement


If X is a discrete random variable with p.d.f. f(x) = {cx if x=1,2,3,4 ; 0 otherwise} where c is a constant.
Find P(1< X =< 3.5)

Homework Equations


I solved for c:
f(x) = 1 = c(1+2+3+4)
10c = 1
c = 1/10

The Attempt at a Solution


I have the following solution:
P(1< X =< 3.5) = f(3.5) - f(1)
= c(3.5) - c(1)
= c(2.5)
=0.25

I am not sure if this is correct. Please help!

Beth
 
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f(x) = 1 = c(1+2+3+4) why ?
isnt it integral of f(x)=1?
i could be totally off though!
 
hmm, possibly... we're not supposed to use calc in my course, or would there be another way of solving it?
 
no idea, I am in a class too, and apparently i have to do that to somethign with 2 variables, and I am so confused! :P sorry i can't help more
 
aw, no problems... this question is so frustrating because it's really difficult to find examples online, and I don't think we did a single example in class of this. I don't want to just guess the answer, but I may have to!
 
bethanyd said:

Homework Statement


If X is a discrete random variable with p.d.f. f(x) = {cx if x=1,2,3,4 ; 0 otherwise} where c is a constant.
Find P(1< X =< 3.5)

Homework Equations


I solved for c:
f(x) = 1 = c(1+2+3+4)
10c = 1
c = 1/10

The Attempt at a Solution


I have the following solution:
P(1< X =< 3.5) = f(3.5) - f(1)
= c(3.5) - c(1)
= c(2.5)
=0.25

I am not sure if this is correct. Please help!

Beth
X is discrete. It can only take on integer values 1, 2, 3, 4. You are violating this condition in your calculation.

Does this help?
 

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