Calculating Projectile Motion: Distance of Cannonball to Black Pearl

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SherazSiddiqu
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Captain Jack Sparrow shoots a cannonball at the black pearl which is located off the cliff that is 100m high. The cannon ball leaves the cannon at 50m/s at 30° to the horizon and hits the Black Pear(the ship) directly.
How far is the Black Pearl(the ship) from the cliff?

Please help thanks.
 
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Here's a picture:
35bvxab.png


So from that you can use this equation to solve:
l_vertical_displacement_equation.png

Delta y is the change in the y which is y2-y1 meaning the change in y will be -100 (NEGATIVE)Edit: I forgot you need to find the x and y components:
v cos (theta) = Vx
V sin (theta) = Vy - You need this 1, other is just for extra practice or w/e. (for this problem)