What is the distance the projectile lands from the base of the cliff?

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SUMMARY

The projectile motion of a basketball thrown off a cliff with an initial velocity of (30.0, 25.0) m/s results in it landing 8.00 seconds later. To determine the horizontal distance from the base of the cliff, the horizontal component of the velocity (vix = 25 m/s) is crucial. The formula for horizontal distance is d = vix * t, leading to a calculated distance of 200 meters from the base of the cliff.

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kenji1992
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Homework Statement


A basketball, thrown off a cliff with a velocity of (30.0, 25.0) m/s, lands on the ground 8.00 s later. In the absence of air resistance, what is the distance the projectile lands from the base of the cliff?

Homework Equations



http://www.ux1.eiu.edu/~cfadd/1150/03Vct2D/proj.html
I found these equations online, but I don't know I should use them.

The Attempt at a Solution



viy=30 m/s
vix=25 m/s
t=8 s
d=?
 
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Think about what vix and viy mean. How do they relate to the figures given in your attachment? Which one would be more helpful in calculating how far from the base of the cliff the basketball travels in 8 sec.?
 

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