Calculating Protein Concentration w/ Bradford Assay

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tvtokyo
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Homework Statement


Hi, I have one more question about the Bradford Assay. This one involves dilution.

Given 1ml of protein A, I am to determine its protein concentration (in mg/ml) using Bradford Assay (with known BSA protein standards).
Also, Under a 5 times dilution, the average absorbance is 0.497.

Homework Equations


The standard curve I obtained is:
upload_2014-12-26_10-35-0.png


The Attempt at a Solution


From the standard curve,
y = 66.717x
With absorbance = 0.497
0.497 = 66.717x
x = 0.00744 ug/ul
Since there is a dilution factor of 5
New x = 0.00744 * 5 = 0.0372 ug/ul = 0.0372 mg/ml ?? (is this correct?)

However, the correct answer is 0.372 mg/ml . What did I did wrongly??
 
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tvtokyo said:
x = 0.00744 ug/ul
Looks good.
tvtokyo said:
New x = 0.00744 * 5 = 0.0372 ug/ul = 0.0372 mg/ml ??
Looks good.

Answer keys in textbooks are "edited/proofed" by "slave labor," aka grad students and post-docs. Often, "half" changes are made after proofing --- problem statements change, and answers don't.
 
In your other question you clearly ignored part of the information given, hard to comment on this one not seeing the whole problem.
 
Is it another part of the same problem? Might be best in future to get all the questions together before asking for help.