Calculating quality of steam after isentropic expansion

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SUMMARY

The discussion focuses on calculating the quality of steam after isentropic expansion from 30 bars to 1 bar. The key formula for determining quality (x) is derived from the entropy equation: s = sf + x(sg - sf), where sf and sg are the entropy values at the respective pressures. The initial state is saturated steam at 30 bars, with entropy values provided as sf = 2.64 and sg = 6.18. The process emphasizes that entropy remains constant during isentropic expansion, allowing for the calculation of quality using steam tables.

PREREQUISITES
  • Understanding of isentropic processes in thermodynamics
  • Familiarity with steam tables and properties of saturated steam
  • Knowledge of entropy and its role in phase changes
  • Ability to manipulate thermodynamic equations
NEXT STEPS
  • Study the derivation and application of the entropy formula for phase transitions
  • Learn how to read and interpret steam tables effectively
  • Explore the concept of quality in steam and its significance in thermodynamic cycles
  • Investigate isentropic processes in other thermodynamic systems
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This discussion is beneficial for students and professionals in thermodynamics, particularly those studying steam properties, phase changes, and isentropic processes in engineering applications.

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Homework Statement


Saturated steam with a pressure of 30 bars is isentropically expanded to a pressure of 1 bar. What is the quality (x) of the steam after expansion?


Homework Equations


No clue. I do have a table containing all necessary data such as temperature, specific volume, internal energy, enthalpy and entropy at the afore mention pressure states.


The Attempt at a Solution


No clue where to start.

The problem is that I have no clue where to start. I know that there is no change in entropy, and that I need to calculate the quality. That is done by a simple formula but there are a couple containing either enthalpy, specific volume or specific energy, and all of this is confusing me!

A nudge in the right direction anyone? :D
 
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Here is a clue: If it is expanded isentropically, what does that tell you about a property after the expansion?
 
LawrenceC said:
Here is a clue: If it is expanded isentropically, what does that tell you about a property after the expansion?

entropy remains constant, meaning that there is no heat exchanged with the exterior. All heat is contained within the system. But does that also mean that the temperature stays the same? I actually don't think so. I do know this formula, but this doesn't get me anywhere:

s= (1-x)s2 +xs1
 
Last edited:
That's not where I'm trying to lead you.

You know the state of the steam at the high pressure because it is saturated. It is expanded isentropically so entropy is constant. You know the final pressure and you know the final entropy of the final state. Therefore you can determine the quality.
 
So you are saying that the entropy of the satured water at both states (1 bar and 30 bar) is constant. In the table it equals sf=2.64 and sg=6.18

the formula is s=sf + x(sg-sf)

what do I put for s then?
 
Initially you have steam at a quality of 100%. That pins down the entropy. After the expansion you have a mixture of liquid water and steam(vapor). If entropy is constant, what do you think you should do?
 
Last edited:
I think I have to calculate the entropy (s) at 30 bars with x=1. Would that be the correct first step?
 
Look it up in steam tables. But yes, that would be a correct first step.
 
Last edited:

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