Calculating Relativistic Mass of Photon & Electron

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SUMMARY

The discussion centers on the concepts of relativistic mass in relation to photons and electrons. It establishes that a photon has no rest mass and its momentum can be derived from its wavelength using the De Broglie relation. The relativistic mass of a photon is often misunderstood, typically represented as the square root of the energy squared minus the momentum squared. For electrons, the speed can be calculated using the wavenumber, with distinctions made between treating the electron as a plane wave versus a wave packet, which affects the calculation of group velocity.

PREREQUISITES
  • Understanding of De Broglie relations and wave-particle duality
  • Familiarity with relativistic mass and energy-momentum equations
  • Knowledge of wave mechanics, specifically wave packets and group velocity
  • Basic principles of quantum mechanics and particle physics
NEXT STEPS
  • Study the concept of relativistic mass and its implications in modern physics
  • Learn about the De Broglie wavelength and its applications to various particles
  • Explore the differences between wave packets and plane waves in quantum mechanics
  • Investigate the relationship between energy, momentum, and relativistic effects in particles
USEFUL FOR

Students of quantum mechanics, physicists interested in particle behavior, and anyone seeking to understand the implications of relativistic effects on mass and momentum.

jalalmalo
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Let me see if I got this right. A photon has no rest mass, and it travels at the speed of light. Knowing the wavelength of the photon will give us the momentum using the De Broglie relation. Now can we say that the momentum of the photon is = relativistic mass of the photon X the speed of light and from that know the relativistic mass, whatever that is?

My other question, take an electron instead. If we know the wavenumber of the electron how do we calculate the speed of the electron.

thanx for your reply

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The Attempt at a Solution

 
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jalalmalo said:
... can we say that the momentum of the photon is = relativistic mass of the photon X the speed of light and from that know the relativistic mass, whatever that is?
If you want to, but you will most likely be misunderstood. Relativistic mass usually refers to sqrt{ E^2 - p^2 }. Many people even use the term to refer simply to E, but I find that a little strange.

jalalmalo said:
My other question, take an electron instead. If we know the wavenumber of the electron how do we calculate the speed of the electron.
This question is a bit ambiguous. If you treat the electron as a plane wave, then you can determine the wave speed as v=omega/k. However, the result may surprise you, and this is probably not what you had in mind. If you treat the electron as a wavepacket (a localized bundle of electron-ness), so that it is more like the classical notion of a particle, then the speed of the packet is, to lowest order approximation, the group velocity. This depends on the nature of the wave packet.
 
But that means that we have to know E and p of the photon, and those are given by De Broglie and Einstein E = h-bar x omega, right? Is it this relativistic mass which is reponsible for the bending of light in gravitational field?
¨
I just started reading quantum mechanics on my own, preparing for next semester, so I hope u bare with me. My confusion is this. When we apply De Broglie to any other particle then the photon do we account for relativistic effects and how do we do that. For instance an electron accelerated to a speed which give relativitic effect, we only know the rest mass. If the electron is then diffracted and the wavelength is measured, can we deduce anything about the velocity of the electron. Thanx for your patience
 

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