Calculating Sample Size for Proportion Estimation

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Homework Help Overview

The discussion revolves around calculating the sample size needed to estimate the proportion of automobile accidents involving pedestrians, with a focus on achieving a specific confidence level and margin of error. The problem is set within the context of statistics, particularly in proportion estimation.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of formulas for sample size calculation, questioning the correctness of the formulas used and the arithmetic involved. There is also a consideration of different scenarios based on known and unknown true proportions.

Discussion Status

Some participants have provided calculations for the sample sizes based on the given scenarios, while others are questioning the validity of these calculations and the formulas used. There is an acknowledgment of the need for confidence in one's work, and a participant expresses a desire to understand the material better.

Contextual Notes

One participant notes that this is their first statistics class, indicating a learning curve and a need for clarification on concepts related to hypothesis testing and sample size determination.

toothpaste666
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Homework Statement


  1. A national safety council wishes to estimate the proportion of automobile accidents that involve pedestrians. How large a sample of accident records must be examined to be 99% certain that the estimate does not differ from the true proportion by more than 0.03? Answer the question if

    (a) the council believes that the true proportion is 0.2.

    (b) no information about the true proportion is given.

The Attempt at a Solution


α = .01 , α/2 = .005, z.005 = 2.575
a) n = p(1-p) [zα/2/E]^2
= (.2)(.8)[2.575/.03]^2 = 1179

b) n = .25[zα/2/E]^2 = (.25)[2.575/.03]^2 = 1842

is this correct?
 
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toothpaste666 said:

Homework Statement


  1. A national safety council wishes to estimate the proportion of automobile accidents that involve pedestrians. How large a sample of accident records must be examined to be 99% certain that the estimate does not differ from the true proportion by more than 0.03? Answer the question if

    (a) the council believes that the true proportion is 0.2.

    (b) no information about the true proportion is given.

The Attempt at a Solution


α = .01 , α/2 = .005, z.005 = 2.575
a) n = p(1-p) [zα/2/E]^2
= (.2)(.8)[2.575/.03]^2 = 1179

b) n = .25[zα/2/E]^2 = (.25)[2.575/.03]^2 = 1842

is this correct?

(1) Have you used the correct formulas?
(2) Have you used the formulas correctly?
(3) Have you made no arithmetical errors?

If your answer to (1)--(3) is YES, then your answer will be correct.

You need to start having confidence in your own work. Frankly, your endless series of similar questions is starting to get old.
 
I apologize. This is the first stats class I have taken, so I wanted to make sure I understand the differences between all the different cases and that I am using the correct statistic for the correct problems. It is because I am reviewing for a final. I won't post any more hypothesis testing questions.
 
You can test the reverse direction. Given a sample of n=1179 with p=0.2, how likely is a deviation of 0.03 or more?
 

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