Calculating Self-Inductance and Capacitance in Parallel Plate Transmission Lines

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SUMMARY

This discussion focuses on calculating self-inductance and capacitance in parallel plate transmission lines. The magnetic field between the plates is derived using Ampere's Circuital Law, leading to the conclusion that the total field is B = μ₀J. The self-inductance per unit length is calculated using the magnetic flux, φ = BA, and the relationship L = Nφ/I. Additionally, capacitance per unit length is determined, and the ratio √(L/C) is expressed in terms of μ₀, ε₀, and geometric factors.

PREREQUISITES
  • Ampere's Circuital Law
  • Magnetic flux calculation
  • Understanding of self-inductance and capacitance
  • Basic electromagnetic theory
NEXT STEPS
  • Study the application of Ampere's Circuital Law in rectangular geometries
  • Learn about calculating magnetic flux in different configurations
  • Research the formulas for self-inductance and capacitance in transmission lines
  • Explore the relationship between inductance, capacitance, and wave propagation in transmission lines
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Electrical engineers, physics students, and anyone involved in the design and analysis of transmission lines and electromagnetic systems.

malindenmoyer
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Two very large parallel conducting plates of very large length l, and width w are separated by a distance d. A current I=Jw flows to the right in the lower plate and to the left in the upper plate. Each of the two currents produces a magnetic field \frac{B}{2} between the two plates.

(a) Show that the total field between the plates is B=\mu_0 J via Ampere's Circuital Law.

(b) Find the flux \phi and the self inductance per unit lenght, \frac{L}{l} for this arrangement.

(c) Find the capacitance per unit length, \frac{C}{l}.

(d) Find \sqrt{\frac{L}{C}} in terms of \mu_0, \epsilon_0 and geometrical factors

My Attempt at Solution
Part (a) is confusing as I have not used the circuital Law for rectangular geometry. I know that Ampere's Law is given by:

\oint_C \mathbf{B} \cdot \mathrm{d}\boldsymbol{\ell} = \mu_0 I_{\mathrm{enc}}

But am confused as to how to apply it as it is not circular geometry.

In part (b) I know that:

\phi=BA

But am not sure as to what area to use, since we know B per part (a)

Solving for flux leads us one step closer to finding the self inductance which is:

L=\frac{N\phi}{I}

But again, I do not know what value to substitute in for N.

I am pretty sure I can find the capacitance per unit length per (c), and then (d) is a matter of combing (b) and (c) so that would be self explanatory. Could somebody help me get this thing started? Please keep in mind that I have a very elementary understanding of this material.

Thanks.
 
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