Calculating Self-Inductance in Coaxial Cables

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SUMMARY

The self-inductance per unit length of a coaxial cable with inner radius 'a' and outer conductor with inner radius 'b' and outer radius 'd' is calculated using the formula μ₀/2π ln(b/a). The assumption that (b-a) >> a and (b-a) >> (d-b) is crucial to simplify the calculations and ensure the validity of Ampere's Law in this context. This assumption allows for the neglect of edge effects and ensures that the magnetic field is uniform across the region of interest.

PREREQUISITES
  • Understanding of coaxial cable geometry
  • Familiarity with Ampere's Law
  • Knowledge of magnetic fields and inductance
  • Basic calculus for logarithmic functions
NEXT STEPS
  • Study the derivation of self-inductance for coaxial cables
  • Learn about the implications of edge effects in electromagnetic theory
  • Explore advanced applications of Ampere's Law in different geometries
  • Investigate the role of permeability (μ₀) in inductance calculations
USEFUL FOR

Electrical engineers, physics students, and anyone involved in the design and analysis of coaxial cables and inductive components.

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Homework Statement



A coaxial cable is made from concentric cylindrical conductors. The radius of the inner conductor is a and the outer comductor has inner radius b and outer radius d. Calculate the self inductance per unit length of the cable. You may assume that (b-a) >> a and (b-a) >> (d-b). Why is this assumption necessary.


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The Attempt at a Solution



Ok so i know that if we take the conducting plates to be think i can work out the inductance to be u0/2pi ln(b/a)

But what difference does it make that the outer one has an inner and outer radius? How do i work it out now?

Also why is the assumption necessary?
 
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Can Ampere's law always be applied without regard for what is outside the amperian loop?

So in this case, in the space between the inner cable and outer cable can i just draw an amperian loop and apply ampere's law? If so - why do i need to assume (b-a) >> a and (b-a) >> (d-b)?

Thanks
 
anyone?
 
should i post this in advanced phys?
 

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