Calculating Silver Chloride Solubility at 25℃

[staka]

Homework Statement

Calculate the solubility of silver chloride at 25℃.

Ksp of silver chloride at 25℃=1.8x10^-10

Homework Equations

AgCl⇔Ag+Cl (I believe)
So, Ksp=[Ag][Cl]

The Attempt at a Solution

All I know is the Ksp of silver chloride at that temperature. I have no idea what to do from here. Do I need to know something about Ag or Cl?

 

[staka]

I attempted..
Ksp=1.8x10^-10
1.8x10^-10=[Ag][Cl]
[Ag]=[Cl]=√1.8x10^-10
=1.3x10^-5M

So I got the solubility for both elements.. do I just add since AgCl⇔Ag+Cl?

 

[staka]

Okay, nevermind. 1.3x10^-5M is AgCl's molar solubility..