How can i calculate the solbilty of silver chloride?

[lioric]

Homework Statement

Ksp of silver chloride is 1.8x10^-10 mol²dm^-6 at RTP

a) calculate the solubility of silver chloride in gdm^-3 in
i) pure water
ii) in 0.1M silver nitrate solution

b)Is silver chloride more soluble in water of in a solution containing silver ions. Why?
c) Why is silver chloride more soluble in aquouse ammonia than in water?

Homework Equations

AgCl = Ag⁺ x Cl^-

The Attempt at a Solution

Ksp = [Ag⁺] x [Cl^-]
1.8x10^-10 = S x S

S= √1.8x10^-10

Which i find the solubility. How do i convert it to g dm^-3?

b)?
c)?

 

[Borek]

What units will your solubility be in?

Before answering b try to solve a ii. c refers to additional reaction that takes place in the ammonia solution.

 

[lioric]

mol/dm3

 

[Infrared]

Well, you know how many moles of AgCl dissolve in a liter of water. Just convert from moles of AgCl to grams of AgCl and realize that a liter is the same volume as a cubic decimeter.

 

[DeeNos]

To convert the solubility to g dm-3, you can use the molar mass of silver chloride to convert from moles to grams. The molar mass of AgCl is 143.32 g/mol. So, if the solubility is 0.001 mol dm-3, then the solubility in g dm-3 would be 0.001 mol dm-3 x 143.32 g/mol = 0.143 g dm-3.

b) Silver chloride is more soluble in a solution containing silver ions because the presence of the silver ions can disrupt the equilibrium of the solubility reaction. This means that more silver chloride will dissolve in the presence of silver ions compared to in pure water.

c) Silver chloride is more soluble in aqueous ammonia because ammonia can complex with the silver ions, making them less available to react with the chloride ions. This shifts the equilibrium towards more silver ions and therefore more silver chloride can dissolve.