How can i calculate the solbilty of silver chloride?

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Homework Statement



Ksp of silver chloride is 1.8x10-10 mol2dm-6 at RTP

a) calculate the solubility of silver chloride in gdm-3 in
i) pure water
ii) in 0.1M silver nitrate solution

b)Is silver chloride more soluble in water of in a solution containing silver ions. Why?
c) Why is silver chloride more soluble in aquouse ammonia than in water?


Homework Equations



AgCl = Ag+ x Cl-


The Attempt at a Solution



Ksp = [Ag+] x [Cl-]
1.8x10-10 = S x S

S= √1.8x10-10

Which i find the solubility. How do i convert it to g dm-3?

b)?
c)?
 
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What units will your solubility be in?

Before answering b try to solve a ii. c refers to additional reaction that takes place in the ammonia solution.
 
Well, you know how many moles of AgCl dissolve in a liter of water. Just convert from moles of AgCl to grams of AgCl and realize that a liter is the same volume as a cubic decimeter.