Calculating Spacetime Interval for Event A

Click For Summary
SUMMARY

The discussion focuses on calculating the time interval between the origin in frame S' and event A, given that the spacetime interval is invariant. The spacetime interval from the origin to event A is confirmed to be 8 lightseconds, while the spatial distance in frame S' is 6 lightseconds. The confusion arises from the terminology used in the problem statement, which should specify "x'" instead of "distance" to clarify that it refers to the spatial component along the x' axis. Understanding these distinctions is crucial for solving the problem accurately.

PREREQUISITES
  • Understanding of spacetime intervals and their invariance
  • Familiarity with Lorentz transformations
  • Knowledge of the concepts of frames of reference in special relativity
  • Basic proficiency in algebra and physics problem-solving
NEXT STEPS
  • Study the principles of Lorentz transformations in special relativity
  • Learn how to calculate spacetime intervals using the formula Δs² = c²Δt² - Δx²
  • Explore the implications of causality in special relativity
  • Review examples of spatial and temporal measurements in different inertial frames
USEFUL FOR

Students studying special relativity, physics educators, and anyone preparing for exams involving spacetime concepts and calculations.

Monster007
Messages
26
Reaction score
1

Homework Statement



The spacetime interval between the origin in frame S and an event, A, is found to be r = 8
lightseconds. In frame S' moving in Standard orientation with respect to S at speed v =
0.5c event A is measured at a distance r' = 6 lightseconds from the origin.

(a) What is the time interval between the origin in S' and event A?

(b) Could an event at the origin and event A be causally related? Explain your answer


Homework Equations




The Attempt at a Solution



I am studying for upcoming exam so the solution isn't as important as understanding the question, but as far as i know the spacetime interval is invariant which is throwing me way off here, I'm certain if i can get part a i understand part b but am completely at sea with part a) any help will be greatly appreciated, cheers.
 
Physics news on Phys.org
Yes, the spacetime interval is invariant. Question (a) asks for the time interval, not spacetime interval.
 
Also, in addition to what BruceW mentioned,

I suspect that when the problem statement said,
"...distance r' = 6 lightseconds..."
it's not asking for the spacetime interval to A, but really asking for the x' component of r. In other words, the distance from the origin to the projection of A onto the x' axis.

It probably would have been clearer if the problem statement was worded, "measured at a distance x' = 6 lightseconds."

In other words, the spacetime interval from the origin to A is 8 lightseconds (true whether one is in S or S', since spacetime intervals are invariant). And in S', the spacial distance (not spacetime distance) from the origin to A is 6 lightseconds. Still in other words, this "6 lightseconds" vector lies along the x' axis itself.

That's my guess as to what the problem statement is trying to say.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 28 ·
Replies
28
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 35 ·
2
Replies
35
Views
7K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
6
Views
2K