Calculating Speed and Rotation for Training Devices

  • Thread starter Thread starter needhelp83
  • Start date Start date
  • Tags Tags
    Formula
Click For Summary

Homework Help Overview

The discussion revolves around calculating speeds and forces related to circular motion, specifically in the context of a banked curve for vehicles and a training device for pilots. The original poster presents two distinct problems involving the dynamics of motion in circular paths, including considerations of friction and centripetal forces.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore equations relating angular velocity to the forces required for circular motion and the relationship between frictional force, mass, and the coefficient of friction.
  • Some participants question the correctness of their setups and calculations, seeking clarification on the application of formulas and unit conversions.
  • There is a suggestion to use diagrams to visualize forces acting on objects in both problems, which may aid in understanding the dynamics involved.

Discussion Status

The discussion is ongoing, with participants actively seeking guidance on their approaches and calculations. Some have offered insights into the need for diagrams to clarify the forces at play, while others express uncertainty about their mathematical setups and conversions.

Contextual Notes

Participants note potential confusion regarding unit conversions and the integration of friction into the equations for banked curves. There is also mention of the specific conditions of the problems, such as the radius of the curves and the coefficients of friction involved.

needhelp83
Messages
193
Reaction score
0
A curve of radius 60 m is banked for a design speed of 90 km/h. If the coefficient of static friction is 0.30 (wet pavement), at what range of speeds can a car safely make the curve?

A device for training astronauts and jet fighter pilots is designed to rotate the trainee in a horizontal circle of radius 10.0 m . If the force felt by the trainee is 7.75 times her own weight, how fast is she rotating? Express your answer in both m/s and rev/s.

I am not sure where to even start. Any help would be appreciated.
 
Physics news on Phys.org
What equations relate the angular velocity of an object to the force required to keep that object rotating around in a circle? And in -1-, what equation relates the sideways frictional force F on an object to its mass (or weight) and the coefficient of friction mu?
 
For the second question:

F=ma
mv^2/r=7.75(m)(g)
mv^2=7.75(m)(9.8 m/s^2)(10)
v^2=759.5
v=27.56 m/s^2

Is this setup correctly?

Now for problem 2
F=mv^2/r=(0.30)(9.8)m
8100 km/h=.06(.30)(9.8)
8100=.1764

Definitely not doing this right? Any suggestions
 
I think that on both of these you will need to draw a diagram to help you understand what forces to calculate.

-1- Draw the banked curve with a mass m on it. Show the forces from gravitational acceleration g and from the friction force mu*N and from the centripetal acceleration.

-2- Draw the trainer chair at the end of the 10m arm. If the problem is stated correctly, it will show that the pilot's chair swivels as the g-forces get higher. When the chair is stationary, it hangs straight down. When the centrifuge is going super-fast, the chair would swing out almost to the horizontal. The swivelling chair is used to always keep the net force on the pilot aimed down through their body, just like in an aircraft pulling g's. If the chair did not swivel, the pilot would be smashed into the outer wall of the centrifuge module, which is not what the trainer is supposed to do. So draw the chair tilted out at some angle -- what determines this angle? And at that angle, what are the various forces acting on the pilot?
 
I understand that this is the formula for a banked curve...
R=v^2tan(theta)/g, but now how do I add in the friction

and for the second question I messed up on my units..
F=ma
mv^2/r=7.75(m)(g)
mv^2=7.75(m)(9.8 m/s^2)(10)
v^2=759.5
v=27.56 m/s

How do I convert from 27.56 m/s to rev/s
 
Any more help?
 

Similar threads

  • · Replies 22 ·
Replies
22
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
Replies
1
Views
1K
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
5K