Calculating Speed of Ball Leaving Spring Gun Barrel

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Homework Help Overview

The problem involves a spring gun that propels a ball through a horizontal barrel. The spring has a force constant and is compressed before releasing the ball. The discussion includes calculating the speed of the ball as it exits the barrel, considering both the spring's potential energy and a constant resisting force acting on the ball.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of energy conservation principles, including potential energy from the spring and kinetic energy of the ball. There are attempts to calculate the speed of the ball under different conditions, including the influence of friction.

Discussion Status

Some participants have identified the position along the barrel where the ball reaches maximum speed, while others are exploring the relationship between potential energy, kinetic energy, and work done against friction. There is ongoing inquiry into the correct application of energy equations to find the maximum velocity.

Contextual Notes

Participants are working under the constraints of the problem as stated, including the effects of a constant resisting force and the need to account for energy lost to friction. There is a noted difficulty in resolving the calculations for maximum velocity, indicating potential misunderstandings or overlooked details in the energy equations.

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Homework Statement


The spring of a spring gun has force constant k = 400 and negligible mass. The spring is compressed 6.00 and a ball with mass 0.0300 is placed in the horizontal barrel against the compressed spring. The spring is then released, and the ball is propelled out the barrel of the gun. The barrel is 6.00 long, so the ball leaves the barrel at the same point that it loses contact with the spring. The gun is held so the barrel is horizontal.

I found the velocity as it leaves the barrel as 6.93 m/s
Then it asks:Calculate the speed of the ball as it leaves the barrel if a constant resisting force of 6.00 N acts on the ball as it moves along the barrel.

I got the 4.9 as the right answer.
Then:For the situation in part B, at what position along the barrel does the ball have the greatest speed? (In this case, the maximum speed does not occur at the end of the barrel.)

And:What is that greatest speed?

Homework Equations



F = -kx
W = 1/2kx2
K = 1/2mv2

The Attempt at a Solution


For finding the first velocity, I used W= 1/2kx2
where x = .06 m, and got it to be .72 J.
Then I set it to 1/2mv2 and got 6.93 m/s, which was right.

For part B, where a 6 N force acts against the bullet I found the work of the force with W = F*D = 6*.06 m = .36
Then I subtracted .36 from .72, which was .36, and set .36 = 1/2mv2, and found the velocity to be 4.9, which was right.

For finding the position along the barrel I tried setting .36 = 1/2kx2, and solving for x, but that didn't work, and without that I can't find the last velocity its asking for. Probably a simple mistake but I can't seem to find where, any ideas?? Thanks for any help.
 
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The ball keeps on accelerating when the force of the spring is greater than the force of friction. After that, the friction takes over and the ball decelerates. So you should solve this equation:

kx = F_{\text{friction}}
 
Thanks, I got the position x where the velocity is greatest, but I still can't get the mac velocity. I tried putting that x value in the spring potential energy equation and setting that equal to the kinetic energy and solving for v, but it said the velocity I got was wrong. This question is bugging me because it should be simple but I seem to keep overlooking something.
 
The mistake is that you didn't include the energy wasted to overcome frictional forces. To obtain the velocity you must consider

E_{\text{kinetic}} = E_{\text{potential}} - E_{\text{friction}}
 

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