Conservation of Energy: Spring PE: Toy gun on spring

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Homework Help Overview

The problem involves a toy gun that uses a spring to launch a Styrofoam ball. The ball is initially at rest against a compressed spring and is released, moving upward against gravitational and frictional forces. The objective is to determine the spring constant of the spring based on the given parameters.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relevant physics concepts, including energy conservation and the forces acting on the system. They raise questions about identifying the system, the contributions to initial and final energy, and the effects of external forces. Some participants also attempt to clarify the terms in the equations used.

Discussion Status

The discussion has progressed with participants sharing their thought processes and equations. One participant initially miscalculated the spring constant but later corrected their approach and arrived at a value of 2240 N/m. There is an ongoing exploration of the physics principles involved, with no explicit consensus on the overall understanding yet.

Contextual Notes

Participants are working within the constraints of the problem statement, including the mass of the ball, the compression of the spring, and the frictional force. The discussion reflects attempts to reconcile different interpretations of energy contributions and the application of the Work-Energy theorem.

DracoMalfoy
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Homework Statement


A toy gun is pointed toward the sky. A Styrofoam ball of mass 10g is at rest against a spring compressed 2cm. The spring is released causing the ball to move upward through the air to a max height of 1m. The air exerts a frictional force of 0.35N on the ball. What is the spring constant(k) of the spring? (Answer: 2240N/m)

Homework Equations


[/B]
.5m⋅Vi^2+.5Kxi^2+mg⋅yi+Ff⋅Δd=.5m⋅Vf^2+.5Kxf^2+mg⋅yf

The Attempt at a Solution


[/B]
I revised the equation as:

.5⋅Kx^2+Ff⋅Δd=mg⋅yf

I took out velocity since it isn't offered in the problem.

m=10g=.01kg
x=2cm=.02m
Δd=1m
Ff=0.35N
K=?

I converted g to kg and cm to m. Then I tried to solve for k.

.5⋅K(.02)^2-.35⋅1=.01⋅9.8⋅1

.0002K-.35=0.98

.0002K=.63

K=.63/.0002

K= 3150

So... I don't know exactly what I did wrong here. I thought that I was on the right path.
 
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Instead of just writing the equation, you should first think of the physics of the problem. Ask yourself the following questions:
1. What is your system?
2. What are the surroundings exerting forces on the system?
3. What is the total initial energy of the system? What are the different contributions to it?
4. What is the final energy of the system?
5. Is the initial energy equal to the final energy? If so, why? If not, why?
6. Can any external forces change the energy of the system?
7. What is the Work-Energy theorem?
8 How do you calculate the work done by the external forces?
Once you answer these questions, the answer should become clear.
 
Chandra Prayaga said:
Instead of just writing the equation, you should first think of the physics of the problem. Ask yourself the following questions:
1. What is your system?
2. What are the surroundings exerting forces on the system?
3. What is the total initial energy of the system? What are the different contributions to it?
4. What is the final energy of the system?
5. Is the initial energy equal to the final energy? If so, why? If not, why?
6. Can any external forces change the energy of the system?
7. What is the Work-Energy theorem?
8 How do you calculate the work done by the external forces?
Once you answer these questions, the answer should become clear.

Ive been thinking about it and trying to figure it out all day.
 
So let us figure out the meaning of each term in your relevant equation. Start with the first term, and state what it is. Also state how you revised the relevant equation and got what you wrote.
 
k is spring constant. x is the compression of the spring. ff is friction force. and then there's displacement. which equals mass multiplied by force due to gravity then that times the displacement again.
.5⋅Kx^2+Ff⋅Δd=mg⋅yf

.5K(.02)^2-.35(1)=(.01)(9.8)(.1)

.0002K-.35=0.098

.0002K=.448

K=.448/.0002

K=2240N/m

I put .98 in the part that I got wrong. I figured it out now thanks.
 

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