MJC8719
- 41
- 0
In Figure 8-34, a 1.2 kg block is held at rest against a spring with a force constant k = 670 N/m. Initially, the spring is compressed a distance d. When the block is released, it slides across a surface that is frictionless, except for a rough patch of width 5.0 cm that has a coefficient of kinetic friction µk = 0.44. Find d such that the block's speed after crossing the rough patch is 1.6 m/s.
onservation of energy:
energy stored in spring = final kinetic energy + energy taken by friction (work)
(1/2) k d2 = (1/2) m v2 - u m g d
or (1/2) * 670 * d2 = (1/2) * 1.2 * 1.62 - 0.44 * 1.2 * 9.8 * 0.05
335 * d2 = 1.536 - 0.259 = 1.277
d2 = 1.277/335 = 0.003812 so d = 0.0617 meters or 6.17 cm
Cannot figure out what I am missing here...
onservation of energy:
energy stored in spring = final kinetic energy + energy taken by friction (work)
(1/2) k d2 = (1/2) m v2 - u m g d
or (1/2) * 670 * d2 = (1/2) * 1.2 * 1.62 - 0.44 * 1.2 * 9.8 * 0.05
335 * d2 = 1.536 - 0.259 = 1.277
d2 = 1.277/335 = 0.003812 so d = 0.0617 meters or 6.17 cm
Cannot figure out what I am missing here...