Calculating Sputnik I's Orbital Period

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SUMMARY

The discussion focuses on calculating the orbital period of Sputnik I, which has a mean orbital radius of 6957 km. The correct formula for this calculation is T^2 = (4π²/GM)r³, where G is 6.67E-11 m³/kg/s² and M is 5.98E24 kg. The radius used in the calculation should include the Earth's radius, leading to a total radius of 6.37E6 + 6.957E6 meters. The expected orbital period is approximately 90 minutes, not the 9.96 seconds initially calculated.

PREREQUISITES
  • Understanding of gravitational constant (G) and its units
  • Familiarity with the mass of the Earth (M = 5.98E24 kg)
  • Knowledge of orbital mechanics and relevant formulas
  • Ability to convert units, specifically kilometers to meters
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  • Study the derivation of Kepler's laws of planetary motion
  • Learn about the implications of orbital mechanics on satellite design
  • Explore the calculation of orbital periods for different celestial bodies
  • Investigate the effects of atmospheric drag on satellite orbits
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Astronomy students, aerospace engineers, and anyone interested in satellite dynamics and orbital calculations will benefit from this discussion.

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1.Sputnik I, the first artificial satellite to circle the planet (October 1957) had a mean orbital radius of 6957 km. Compute its period in seconds



2. I am using the equation T^2 = R^3/C



3. I converted 6957 km to AU's which equals 4.638 E-5. When I plug in the numbers, and convert it to seconds, I come up with 9.96 seconds. Am I using the correct formula?

Thanks for your help.
 
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Use:

T^2 = (\frac{4\pi^2}{GM})r^3

G = 6.67E-11 (metres-cubed per kilogram per second-squared)
M = 5.98E24 (kilograms)
r = 6.957E6 (metres)
 
Last edited:
Hi Rake-MC,

Rake-MC said:
Use:

T^2 = (\frac{4\pi^2}{GM})r^3

G = 6.67E-11 (metres-cubed per kilogram per second-squared)
M = 5.98E24 (kilograms)
r = 6.37E6 + 6.957E6 (metres)


The way I read the problem, I think the radius of the Earth is included in the 6957km given. Does that sound right to you?
 
Hmm it's a bit ambiguous, but thinking logically I would entirely agree that the radius of the Earth is included in the 6957km. Clearly I was thinking purely mathemtically and not realistically.
 
My professor told me to use formulas V=2 pi r/T and V^2 = GM/R, but my answer is still incorrect. Any suggestions?

Thanks
 
Using either:

T^2 = (\frac{4\pi^2}{GM})r^3

Or the formula your professor gave you will yield the same answer.

It looks like it'll be approximately 90 minutes.
 

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