Calculating Sputnik I's Orbital Period

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Homework Help Overview

The discussion revolves around calculating the orbital period of Sputnik I, the first artificial satellite, using its mean orbital radius. The subject area includes orbital mechanics and gravitational physics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply Kepler's third law using a specific formula but questions its correctness after obtaining an unexpected result. Other participants suggest alternative formulas and clarify the parameters needed, including the potential inclusion of Earth's radius in the given orbital radius.

Discussion Status

Participants are exploring different formulas and interpretations of the problem. Some guidance has been offered regarding the formulas to use, and there is a recognition of ambiguity in the problem setup concerning the orbital radius.

Contextual Notes

There is a discussion about the potential ambiguity in whether the given mean orbital radius includes the radius of the Earth. Additionally, there are references to specific constants and values that may be relevant for the calculations.

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1.Sputnik I, the first artificial satellite to circle the planet (October 1957) had a mean orbital radius of 6957 km. Compute its period in seconds



2. I am using the equation T^2 = R^3/C



3. I converted 6957 km to AU's which equals 4.638 E-5. When I plug in the numbers, and convert it to seconds, I come up with 9.96 seconds. Am I using the correct formula?

Thanks for your help.
 
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Use:

T^2 = (\frac{4\pi^2}{GM})r^3

G = 6.67E-11 (metres-cubed per kilogram per second-squared)
M = 5.98E24 (kilograms)
r = 6.957E6 (metres)
 
Last edited:
Hi Rake-MC,

Rake-MC said:
Use:

T^2 = (\frac{4\pi^2}{GM})r^3

G = 6.67E-11 (metres-cubed per kilogram per second-squared)
M = 5.98E24 (kilograms)
r = 6.37E6 + 6.957E6 (metres)


The way I read the problem, I think the radius of the Earth is included in the 6957km given. Does that sound right to you?
 
Hmm it's a bit ambiguous, but thinking logically I would entirely agree that the radius of the Earth is included in the 6957km. Clearly I was thinking purely mathemtically and not realistically.
 
My professor told me to use formulas V=2 pi r/T and V^2 = GM/R, but my answer is still incorrect. Any suggestions?

Thanks
 
Using either:

T^2 = (\frac{4\pi^2}{GM})r^3

Or the formula your professor gave you will yield the same answer.

It looks like it'll be approximately 90 minutes.
 

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