Calculating standard deviation for average force

[jb007]

Homework Statement

I am stuck on the last problem.

Homework Equations

Just the error propagation equations

The Attempt at a Solution

I initially used the multiplication error propagation formula. So the average force would be the impulse divided by the time, the same thing as the impulse times 1/time. F_avg = I⋅1/t. So the deviation for force would be the absolute value of I times 1/(deviation of time)? But this is wrong, as I get 131, a number that wouldn't make sense. How do I find the deviation for F_avg? I feel like I might have to use some of my other data...

 

[RUber]

According to the reference at http://huss.covenant.edu/academics/physics/courses/GenPhys1/labs/AveragesAndErrors.pdf
The formula you need to solve is
$\frac{\delta(x/y) }{x/y} = \frac{\delta(x) }{x}+\frac{\delta(y) }{y}$

Doing that, I got something near 0.8.

 

[priyadharshini]

your doubt can be clarified with this calculator my friend.,

with force, impulse and time alternatively as well.

https://www.easycalculation.com/physics/classical-physics/impulse-time.php with average force