Calculating Standard Error of Mean with Significant Figures

Click For Summary
The standard error of the mean (σmean) is calculated using the formula σmean = σ/sqrt(n), resulting in a value of approximately 0.0075 when rounded. Since the sample size (n = 29) is considered error-free, it can be treated as having infinite significant figures, allowing σmean to retain four significant figures. The discussion highlights the importance of reporting significant figures accurately in lab reports, as discrepancies can affect grading. The user plans to address a grading issue with their teaching assistant regarding the significant figures in their report. Accurate representation of significant figures is crucial in scientific reporting.
emeraldskye177
Messages
26
Reaction score
0

Homework Statement



In a physics lab, Logger Pro software generated statistical estimators such as the standard deviation σ = 0.04021 of a sample of size n = 29.

Among other things, I must calculate the standard error of the mean σmean.

My question is: Must σmean have four sig figs or two (i.e., do I account for the number of sig figs in the sample size, even though n has no error associated with it)?

Homework Equations



σmean = σ/sqrt(n)

where σ is the standard deviation of the distribution and n is the sample size.

The Attempt at a Solution



σmean = σ/sqrt(n) = 0.04021/sqrt(29) = 0.007467 or 0.0075?
 
Physics news on Phys.org
*edit* I misread your initial question...sorry.
Since your sample size is error free, you can consider that as an infinite number of sig. figs. and keep 4.

Significant figures is easiest to understand in scientific notation.
If you write it as 7.467 x 10^(-3), it is clear that this version has 4 significant figures.
 
Presumably the count is accurate and must be an exact integer. It should be treated as though it has infinite precision.
 
Thanks all. In my lab report, I did it the correct way (i.e., reported the answer to 4 sig figs), but the TA docked me marks with the comment "sig figs", so I will have to take this up with the lab coordinator. Thanks again for your answers.
 
emeraldskye177 said:
In a physics lab, Logger Pro software generated statistical estimators such as the standard deviation σ = 0.04021 of a sample of size n = 29.
What was the number of significant digits in the data for which these σ were calculated?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
4
Views
3K
  • · Replies 19 ·
Replies
19
Views
7K
Replies
7
Views
2K
Replies
15
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
1
Views
1K
  • · Replies 12 ·
Replies
12
Views
4K
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K