- #1

VitaminK

- 46

- 4

- Homework Statement
- Hey everyone,

I recently performed a lab at school where I had to drop a bouncy ball, let it bounce 4 times, and after each bounce write down the height to which the ball bounces. The procedure was repeated 4 times in total. In each of the four trials, I had variations in the observed heights. Now I have to calculate margin of error.

- Relevant Equations
- margin of error: sx̄ = s/√N

**Bounce 1, Trial 1-4:**

ha (height after bounce)

(0.74+0.67+0.69+0.73)/4=0,7075 this is my mean value.

Standard Deviation, s: 0.033040379335998 (calculated the value using an online standard deviation calculator)

Sample size N: 4

sx̄ = s/√N = 0.033040379335998/√4≈ 0.0165

At a 95% confidence interval the margin of error is 0,0165*1,96=0,03234

So I'm guessing the answer for the first bounce is ±0,032m.

Is this correct and is there an easier way to calculate?