Calculating strain from wave speed and tension in a wire

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An aluminum wire under zero tension has its tension increased by reducing the temperature, affecting its equilibrium length. The transverse wave speed is given as 100 m/s, with the wire's cross-sectional area at 5.0 x 10^-6 m², density at 2.7 x 10³ kg/m³, and Young's modulus at 6.8 x 10¹⁰ N/m². The calculations show that the mass per unit length (μ) is 1.35 x 10^-2 kg/m, leading to a tension (τ) of 135 N. The correct strain (ΔL/L) is calculated to be 4.0 x 10^-4 after verifying unit consistency. Accurate unit tracking is emphasized to avoid mistakes in calculations.
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Homework Statement



Just wanted to check my work on this one.

An aluminum wire is clamped at each end under zero tension at room temperature. The tension in the wire is increased by reducing the temperature which results in a decrease in the wire's equilibrium length. What strain (ΔL/L) will result in a transverse wave speed of 100 m/s? Take the cross-sectional area of the wire to be 5.0 x 10-6 m2. The density of aluminum is ρ = 2.7 x 103 kg/m3 and Young's modulus is Y = 6.8 x 1010 N/m2.

Homework Equations


[/B]
v = √(τ/μ), F/A = E(ΔL/L)

The Attempt at a Solution


[/B]
100 m/s = √(τ/μ) μ = ρ x A = 2.7 x 103 kg/m3 x 5.0 x 10-6 m2 = 1.35 x 10-2 kg/m. τ = v2μ = 1 x 104 m2/s2 x 1.35 x 10-2 kg/m = 135 N = F/A. F/A = E(ΔL/L), 135 N = 6.8 x 1010(ΔL/L). ΔL/L = 2.0 x 10-9.

Does this look correct?
 
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135 N ≠ F/A

Check your units.
 
Oh, right...F/A would be 135 N / 5.0 x 10-6 m2 = 2.7 x 107 N/m2?
 
Correct.

I always strongly recommend to include all your units in all your calculations. That way you can catch easy mistakes like this.
 
So ΔL/L = 4.0 x 10-4?
 
Looks about right.
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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