Calculating Tangential Velocity: 0.45kg Ball, 45N Force

Click For Summary

Homework Help Overview

The discussion revolves around calculating the tangential velocity of a ball attached to a string, given its mass and the force acting on it. The subject area includes concepts of circular motion and centripetal acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are discussing the relationship between centripetal force, acceleration, and tangential velocity. There are attempts to use formulas such as v = r * omega and F = m * r * omega^2 to find the necessary values. Questions about the clarity of calculations and the definitions of terms are also raised.

Discussion Status

The discussion is ongoing, with some participants seeking numerical calculations while others are exploring the relationships between the variables involved. There is no explicit consensus yet, but guidance regarding the definitions of centripetal force and acceleration has been provided.

Contextual Notes

Participants are working within the constraints of a homework problem, which may limit the information available for calculations. There is a focus on ensuring clarity in the mathematical relationships being discussed.

sw3etazngyrl
Messages
12
Reaction score
0
Suppose a 0.45kg ball is attached to a 1.00m long string. the force keeping the ball oving in a circular path is 45 N. What will the ball's centripetal acceleration and tangential velocity be?



I got the first part, but I'm not sure how to get the 2nd part.



So, I'm using v=r*omega. To find omega, I want to use F=mr*omega^2. Will that work?
 
Physics news on Phys.org
Will you show the calculations in numbers?
 
sw3etazngyrl said:
So, I'm using v=r*omega. To find omega, I want to use F=mr*omega^2. Will that work?
Probably. BTW, the bold face is hard to read.
 
The force keeping the ball in circular path is the centripetal force. Since f=ma, and we know that "a" must be the centripetal acceleration. What is centripetal acceleration equal to (you already found this, from there you should realize the a_cent is also equal to something else).
 

Similar threads

Replies
12
Views
2K
  • · Replies 12 ·
Replies
12
Views
1K
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
17
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K