Calculating Tension: Basic Formula?

  • Thread starter Thread starter ScienceGirl502
  • Start date Start date
  • Tags Tags
    Tension
Click For Summary
Calculating tension in a cable or string requires analyzing the specific problem at hand. In equilibrium situations, the tension at one end of the string matches the gravitational force acting on the object, such as a lamp, resulting in tension equal to mg. When considering a cable with mass, the tension increases at the attachment point to account for the combined weight of the lamp and the cable. For massless cables, tension remains constant throughout, but this changes in accelerating systems or when friction is involved. Understanding the underlying concepts is crucial for accurately determining tension rather than just applying formulas.
ScienceGirl502
Messages
13
Reaction score
0
is there a basic formula for calculating tension?

like the tension in a cable or string holding up a sign, etc.
 
Physics news on Phys.org
You have to look at the particular problem for calculating the tension.

In equilibrium problems, the basic idea is that the tension in a string at one end is of that magnitude as to keep the object at that end stationary.
If there's a lamp of mass m hanging down from a cable vertically,
then gravity acts on the lamp with a force -mg (I take up as the positive direction).
Since the net force on the lamp is zero, the tension in the cable at that end is mg.
The tension in the cable where it is attached to the ceiling is greater, since the combined gravitational force acting down is -g(m+m_c). Where m_c is the mass of the cable.

If the cable is massless, the tension always has the same magnitude throughout.

In general, every problem needs its own ideas to solve (eg. for the tension). The important thing is to understand the concept and being able to apply it. Not just learning formulas and plugging in the data.
 
"If the cable is massless, the tension always has the same magnitude throughout."
For accelerating systems, this is not always correct (for example a rope not moving relatively to a rotating pulley, or when there is kinetic friction between the rope&pulley).
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 18 ·
Replies
18
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
13
Views
1K
  • · Replies 19 ·
Replies
19
Views
2K
Replies
21
Views
837
  • · Replies 27 ·
Replies
27
Views
3K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K