Calculating Tension in a Flying Pig's Rope: Centripetal Force Explained

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SUMMARY

The discussion centers on calculating the tension in a rope supporting a flying pig with a mass of 0.1618 kg, which is undergoing uniform circular motion. The centripetal force required for this motion has been determined to be 0.955 N. The tension in the rope is directly related to this centripetal force, as it provides the necessary force to keep the pig in circular motion. The tension can be equated to the centripetal force in this scenario, as there are no other forces acting vertically on the pig.

PREREQUISITES
  • Understanding of centripetal force and its formula
  • Basic knowledge of Newton's laws of motion
  • Familiarity with uniform circular motion concepts
  • Ability to perform calculations involving mass and force
NEXT STEPS
  • Study the formula for centripetal force: F = (m*v^2)/r
  • Learn about the relationship between tension and centripetal force in circular motion
  • Explore examples of uniform circular motion in real-world scenarios
  • Investigate the effects of varying mass and radius on tension and centripetal force
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of circular motion and the forces involved in maintaining that motion.

Centripetal X
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My mission:

Find the force of tension in the rope supporting your flying pig. No joke. We have a pig with mass .1618 kg that is attached to a string of "negligable mass". It flies around from a supsended point in uniform circular motion. Using the radius and period I found, I got the centripetal force to be .955 N. How do I relate this into the force of tension?
 
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Where do you suppose the centripetal force is coming from?
 

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