Calculating Tension in a Static System

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Discussion Overview

The discussion revolves around calculating the tension in a static system, specifically focusing on vector directions and their implications in the context of a homework problem. Participants explore the relationships between tension vectors and their orientations.

Discussion Character

  • Homework-related, Conceptual clarification, Technical explanation

Main Points Raised

  • One participant expresses confusion regarding the signs of the tension vector compared to the answer provided in the textbook.
  • Another participant clarifies that the tension vector points from point B towards point A, while the original participant had created a vector pointing from A to B.
  • There is a discussion about the difficulty of determining vector direction without visual aids, such as arrows.
  • A later reply mentions the presence of a weight acting downwards, indicating that the tension must act upwards to counteract this force.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct signs for the tension vector, and there is ongoing clarification about vector directions and their physical implications.

Contextual Notes

Participants express uncertainty about vector directionality and the impact of external forces, such as weight, on the tension calculations.

thinkcentre12
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Homework Statement

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Homework Equations



The answer in the back on the book shows 4.06i -7.61j + 5.07k. I do not understand why my signs are backwards.

The Attempt at a Solution



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I ended with -4.06i +7.61j - 5.07k
 
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The tension involved is a vector that points from B towards A. You've created a vector rab that points from A to B.
 
ok thank you. Since i did not see an arrow i was not sure which direction to pick. How did you tell?
 
thinkcentre12 said:
ok thank you. Since i did not see an arrow i was not sure which direction to pick. How did you tell?
It's difficult to push with a cable :)
 
gneill said:
The tension involved is a vector that points from B towards A. You've created a vector rab that points from A to B.

gneill said:
It's difficult to push with a cable :)
That is a good point. Thank you
 
thinkcentre12 said:
That is a good point. Thank you

Additionally, there is a weight pulling the boom downwards (or in the negative z-direction). In order to counteract this, the cable needs to pull it upwards (positive z-direction).
 

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