Calculating Tension in Ropes for a Suspended Circus Performer

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SUMMARY

The discussion focuses on calculating the tension in two ropes supporting a 76.0-kg circus performer clinging to a trapeze. The equations used are based on static equilibrium, specifically ∑Fx = T2cos10 - T1sin(15) = 0 and ∑Fy = T1cos(15) + T2sin(10) - m*g = 0. Participants confirm the validity of the equations and suggest alternative representations, such as calculating the angle of T1 as 75 degrees. The solution involves applying trigonometric functions to resolve the forces acting on the performer.

PREREQUISITES
  • Understanding of static equilibrium in physics
  • Knowledge of trigonometric functions and their applications
  • Familiarity with free body diagrams
  • Basic grasp of Newton's laws of motion
NEXT STEPS
  • Study the principles of static equilibrium in more complex systems
  • Learn how to create and analyze free body diagrams
  • Explore tension calculations in different configurations of ropes
  • Investigate the effects of angles on force components in physics
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Physics students, educators, and anyone interested in mechanics and tension calculations in real-world applications.

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Homework Statement


After a mishap, a 76.0-kg circus performer clings to a
trapeze, which is being pulled to the side by another circus
artist, as shown here. Calculate the tension in the two ropes
if the person is momentarily motionless. Include a free body diagram in your solution
MhHZ9mj.png


Homework Equations


∑Fx = T2cos10-T1sin(15)=0
∑Fy=T1cos(15)+T2sin(10)-m*g=0

The Attempt at a Solution


Here is my free body diagram:

nyHF38Q.png


I am not sure are my equations valid.
 
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Welcome to the PF. :smile:

Looks good so far, so keep on going...
 
Is it also valid if I calculate angle of T1 as 90 - 15 = 75 and write equations as:

Σx = -T1cos(75) + T2cos(10) = 0
Σy =T1sin(75) + T2sin(10) - m*g = 0
 

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