Calculating the Angle for a Collision of Two Particles

[AnnaSuxCalc]

Homework Statement

Particle A moves along the line y = 29 m with a constant velocity of magnitude 2.8 m/s and directed parallel to the x axis. At the instant particle A passes the y axis, particle B leaves the origin with zero initial speed and constant acceleration of magnitude 0.42 m/s2. What angle θ between and the positive direction of the y-axis would result in a collision?

Homework Equations

x = x₀ + v_0xt + 1/2 (a_xt²)

y = y₀ + v_0yt + 1/2 (a_yt²)

Particle A
y = 29
v_x = 2.8
y₀ = 29
a = 0

Particle B
v₀ = 0
a = 0.42
y₀ = 0
x₀ = 0

 

[AnnaSuxCalc]

Homework Statement

Particle A moves along the line y = 29 m with a constant velocity of magnitude 2.8 m/s and directed parallel to the x axis. At the instant particle A passes the y axis, particle B leaves the origin with zero initial speed and constant acceleration of magnitude 0.42 m/s2. What angle θ between and the positive direction of the y-axis would result in a collision?

Homework Equations

x = x₀ + v_0xt + 1/2 (a_xt²)

y = y₀ + v_0yt + 1/2 (a_yt²)

Particle A
y = 29
v_x = 2.8
y₀ = 29
a = 0

Particle B
v₀ = 0
a = 0.42
y₀ = 0
x₀ = 0

PLEASE HELP I've been stuck on this question for DAYS!

 

[jhae2.718]

You need to come up with equations giving the x and y positions of A and B as functions of time.

Use the equations you have to get expressions of x_a(t),y_a(t),x_b(t), and y_b(t).

Then, what conditions do you need for the two projectiles to collide? You can use these conditions to eliminate the parameter t and solve for theta.