Calculating the Best Bet: Solving the Problem of Roulette Odds

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SUMMARY

The discussion focuses on calculating the expected value of bets in roulette, specifically analyzing a scenario where a player bets $1 on a roulette wheel with 38 spaces. The average return for this bet is calculated to be -$0.0526, leading to the conclusion that playing is not a favorable decision. A hypothetical scenario is presented where a player dreams of a roulette wheel that offers an average return of $0.44 per $1 bet, leading to the determination that this fantasy roulette wheel contains 25 spaces. Key contributors to the discussion include members Sudharaka, soroban, and Reckoner.

PREREQUISITES
  • Understanding of expected value in probability
  • Basic knowledge of roulette game mechanics
  • Familiarity with mathematical calculations involving fractions
  • Ability to interpret and manipulate algebraic equations
NEXT STEPS
  • Study the concept of expected value in greater detail
  • Learn about probability theory and its applications in gambling
  • Explore different types of bets in roulette and their odds
  • Research strategies for minimizing losses in casino games
USEFUL FOR

This discussion is beneficial for mathematicians, gamblers, and anyone interested in understanding the mathematical principles behind casino games, particularly roulette. It is also valuable for those looking to make informed financial decisions based on expected value calculations.

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You and your friends are going to Vegas. They find a roulette table and while watching your friends play, you ponder if this is mathematically a good decision in the long run. You choose to bet \$1 while you think.

There are 38 spaces on the wheel and you bet on one number of out of the 38 being chosen. If you choose correctly you will receive \$35, if not then you lose your bet. You are good at math and quickly calculate that your average return for this \$1 bet is -\$0.0526 so you decide not to play anymore.

While asleep you are dreaming about a wonderful fantasy roulette where you average \$0.44 on every \$1 bet. Assuming you still get \$35 for choosing the correct number and lose \$1 when not choosing the correct number, how many spaces does this fantasy roulette wheel contain?

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Congratulations to the following members for their correct solutions:

1) Sudharaka
2) soroban
3) Reckoner

Solution (from soroban):

[sp]Comments from Jameson: The roulette wheel is a great example of how the casino makes money. All possible bets have a negative expected value for the player in the long run, that is to say, if you play long enough you will lose your money even if you have big wins. If you didn't know before, after reading this solution you should now be able to make some useful calculations about roulette.

A main concept used here is expected value. If you haven't studied this before, I highly recommend doing so. It can be applied to investments and other financial decision, or even general decisions for that matter.

Solution below.

Let n = number of spaces.

\tfrac{1}{n} of the time you will win \$35.

The other \tfrac{n-1}{n} of the time you will lose \$1.

Your expected value is \$0.44.

Hence: .[/color]\frac{1}{n}(35) + \frac{n-1}{n}(-1) \:=\:0.44

Multiply by n\!:\;35 - (n-1) \:=\:0.44n

. . . . . . . . . . . . [/color]35 - n + 1 \:=\:0.44n

. . . . . . . . . . . . . . . . . . . [/color]36 \:=\:1.44n

. . . . . . . . . . . . . . . . . . . . [/color]n \:=\:\frac{36}{1.44} \:=\:25

This roulette wheel has 25 spaces.
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