Calculating the Center of Mass of a Boat with 3 People

Click For Summary

Homework Help Overview

The problem involves calculating the center of mass of a boat that contains three people with specified weights and distances from each other. The weights of the individuals and the boat are provided, along with their respective positions in relation to the ends of the boat.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the importance of measuring distances from a consistent reference point, such as the front of the boat. There are questions about the correct placement of the boat's mass and how to incorporate it into the center of mass calculation. Some participants express uncertainty about the distances and the total mass of the system.

Discussion Status

The discussion is ongoing, with participants providing hints and suggestions for clarifying the problem setup. There is no explicit consensus on the correct approach yet, but guidance has been offered regarding the need for consistent distance measurements and the importance of visualizing the problem through diagrams.

Contextual Notes

Participants are navigating potential confusion regarding the distances of individuals from the ends of the boat and how to accurately account for the boat's mass in the calculations. There is mention of drawing diagrams to aid understanding, indicating a need for clearer visualization of the problem.

Susanne217
Messages
311
Reaction score
0

Homework Statement



Lets image the following a boat has three people in it

A has a mass of 120lb
B has a mass of 180lb
C has a mass of 160lb

and the boat has a mass of 120lb

also distance from person A to the front of the boat is 2 feet and distance from person A to person B is 8 feet and distance from person B to person C who is at the end of boat is 8 feet. What is the center of mass of the boat

Homework Equations



x = (m_1*x_1 + ...+ m_n * x_n)/M

where is the mass of all 3 people and the boat.

The Attempt at a Solution



the center of mass is then

x = \frac{120lb \cdot (2) + 180lb \cdot (8) + 160lb \cdot 16 }{120+180+160+120}

Is this right?
 
Physics news on Phys.org
Make sure you measure the distance of each mass from the same point--for example, from the front of the boat. And don't forget the mass of the boat itself--where is it located?
 
Doc Al said:
Make sure you measure the distance of each mass from the same point--for example, from the front of the boat. And don't forget the mass of the boat itself--where is it located?

What I'm unsure about is the distance from each end of the boat is exactly 8 feet to the center of the boat is the mass of the boat by any chance the mass at the center of the boat + the mass of boat??

Which means is the mass at the center is 180lb and mass of the person is 120lb

then the mass of the boat is 300lb?

and I multiply this by 8 this to the top of center of mass fraction is previous post??
 
The mass of the boat is given as 120 lb. But the center of the boat is not 8 feet from the end. Hint: Use the distances given to figure out the length of the boat. (And the correct distance of each person from the end.) Draw yourself a diagram.
 
Consider this a rudimentary ascii of the boat and its passengers:
(F) is the front of the boat, ABC are the people and (B) is the back,with each hyphen(-)marking 1ft

(F)--A--------B--------C(B)
120 180 160

and we know that the boat is of mass 120lb, so that can be added where?

make sure you do what the Doc says and always calculate moments from the same point =].
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
1K
  • · Replies 7 ·
Replies
7
Views
7K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 16 ·
Replies
16
Views
27K
  • · Replies 26 ·
Replies
26
Views
5K