Calculating the change of momentum in a system

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SUMMARY

The change in momentum for the given scenario is calculated using the formula delta p = p(final) - p(initial). For a ball with an initial momentum of 10 kg-m/s [E] that rebounds with a momentum of 6 kg-m/s [W], the change in momentum is determined to be -4 kg-m/s. This negative value indicates a reversal in direction, confirming that momentum is a vector quantity. The calculation assumes a head-on impact without any angular considerations.

PREREQUISITES
  • Understanding of momentum as a vector quantity
  • Familiarity with the equation delta p = p(final) - p(initial)
  • Basic knowledge of physics concepts related to collisions
  • Ability to interpret directional indicators in momentum calculations
NEXT STEPS
  • Study vector addition and subtraction in physics
  • Learn about conservation of momentum in elastic and inelastic collisions
  • Explore more complex momentum problems involving angles and multiple objects
  • Review the principles of impulse and its relationship to momentum changes
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and momentum, as well as educators looking for clear examples of momentum calculations in collision scenarios.

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Homework Statement



A ball with momentum of 10 kg-m/s [E] hits an object and rebounds with momentum of 6 kg-m/s [W]. What was the change in momentum?

Homework Equations



delta p=p(final)-p(initial)

The Attempt at a Solution



delta p=p(final)-p(initial)
delta p=(6 kg-m/s)-(10 kg-m/s)
delta p= -4 kg-m/s

This problem seems so simple, and yet it's in the middle of a worksheet full of really hard problems, so I just wanted to make sure I'm doing it right.
 
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I am assuming that impact is head on i.e. there are no angles involved.

Do not forget that momentum is a VECTOR.
Hence if to the RHS one takes it as positive, it must be taken as negative when it reverses direction.
 

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