Calculating the conductivity of a solution of HCl and HAc

Click For Summary
SUMMARY

The discussion focuses on calculating the specific conductivity (k) and resistance (R) of a solution containing 0.01 M hydrochloric acid (HCl) and 0.1 M acetic acid (HAc). The molar conductivity of HAc is given as Λm = 5.14 cm2S/mol, and the cell constant is Kcell = 0.5652. The relationship between conductivity and concentration is established through the equations k = c Λm and R = Kcell / k. The impact of adding a strong acid like HCl on the conductivity of HAc is also addressed, with the use of an ICE table being suggested as a method to simplify the calculations.

PREREQUISITES
  • Understanding of molar conductivity and its calculation
  • Familiarity with the concept of cell constants in conductivity measurements
  • Knowledge of the ICE table method for equilibrium calculations
  • Basic chemistry knowledge regarding strong and weak acids
NEXT STEPS
  • Research the effects of strong acids on the conductivity of weak acids
  • Learn how to construct and utilize ICE tables for equilibrium problems
  • Study the relationship between concentration and conductivity in electrolyte solutions
  • Explore the calculation of molar conductivity for different acids
USEFUL FOR

Chemistry students, educators, and professionals involved in analytical chemistry or solution chemistry who are looking to deepen their understanding of conductivity in mixed acid solutions.

Sabe
Messages
2
Reaction score
0

Homework Statement


I need to calculate the specific conductivity k and the resistance R of a cell containitng 0.01 M HCl and 0.1 M acetic acid (HAc).
I know the molar conductivity of HAc: Λm = k/c = 5.14 cm2S/mol.
I also know Ka (HAc) = 1.795 *10-5.
I know the cell constant Kcell = R*k = 0.5652.
(It may be ok to look up some constants for conductivity of HCl etc.)

What I'm struggling with is: How is the conductivity of the HAc affected by adding a strong acid?

Homework Equations


k = c Λm
R = Kcell /k
 
Physics news on Phys.org
Sabe said:
What I'm struggling with is: How is the conductivity of the HAc affected by adding a strong acid?

Do you know how to use ICE table? If so, problem is trivial.
 
Yes! I got it now, thank you :)
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 2 ·
Replies
2
Views
10K
Replies
5
Views
6K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
4
Views
4K
Replies
5
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 20 ·
Replies
20
Views
7K