Calculating the density parameter (Cosmology)

2 replies · 2K views · last reply
Hangst
Messages
12
Reaction score
0

Homework Statement



Decide the density parameter from the following data:

z=0.04, m= 17.38 and σ=0.19

Homework Equations



Definition of the density parameter:

Equation: Omega subscript 0 equals rho divided by rho subscript c, the density parameter defined as current density over critical density.


Where p0 is the current density and pc is the critical density.

The Attempt at a Solution



I feel like I don't have enough information to calculate it as I'm unable to calculate the current density of the universe. Any help is greatly appreciated! Thanks.
 
Two pictures of an attempt at a solution (no units)>

Worked Mathematica-style calculation of the density parameter: solve z = v/c = 0.04 for v, giving v = 1.199996 x 10^12 m/s; isolate distance x = 1.615068641 x 10^10; volume V = 1.741299136 x 10^31; density rho = 9.981053595 x 10^-31; then Omega_0 = rho/rho_c.


and

Typeset equations for critical density rho_c = 3 H_0^2 / (8 pi G) and density parameter Omega_0 = 9.981053595 x 10^-31 / (3 x 74.3^2 / (8 x 3.14 x 6.67 x 10^-11)), with blue computed results rho_c = 3 H^2 and Omega_0 = 1.009771187 x 10^-43 on the right.