- #1
- 560
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I've understood that the main evidence for a non-zero ##\Omega_\Lambda## comes from supernova 1a measurements where one measures the redshifts along with the luminosity distances (equivalently magnitude) of the supernovae and, plots them against each other, then compares the result with theoretically derived curves for different values of cosmological parameters and find the parameter choices corresponding to the best fit. (One example of such plots are shown here.)
From what I have read, the only two parameters that are being varied is ##\Omega_m## and ##\Omega_\Lambda## from which one gets the result approximately ##\Omega_\Lambda \approx 0.7## and ##\Omega_m \approx 0.3## supporting the claim that the universe is flat since ##\Omega_\Lambda + \Omega_m \approx 1##.
But here is the thing: since ##\Omega_k## was not varied, did we not already assume ##\Omega_k = 0## in the first place? Might it not have been the case that by also varying ##\Omega_k## this could've lead to a better fit with other parameter values than in the above result?
Or is there a good argument for why one can neglect ##\Omega_k## in the curve-fitting procedure?
From what I have read, the only two parameters that are being varied is ##\Omega_m## and ##\Omega_\Lambda## from which one gets the result approximately ##\Omega_\Lambda \approx 0.7## and ##\Omega_m \approx 0.3## supporting the claim that the universe is flat since ##\Omega_\Lambda + \Omega_m \approx 1##.
But here is the thing: since ##\Omega_k## was not varied, did we not already assume ##\Omega_k = 0## in the first place? Might it not have been the case that by also varying ##\Omega_k## this could've lead to a better fit with other parameter values than in the above result?
Or is there a good argument for why one can neglect ##\Omega_k## in the curve-fitting procedure?